H A T
* C U P
---------------
E I U I
E A R T
E U P I
------------------
H I E E E I
-----------------

• 345
  *876
  ______
  2070
  2415
  2760
  ______
  302220
• 11 years agoHelpfull: Yes(8) No(6)
• from u*t=t, we can say t=5,and multiples of T have 5,0 as last digits..hence T=5 and I=0..
  
  now from last 2 column U+5=10+E..(since if there is no carry then the result of 3 column would be R)..
  
  from first 2 column we get E+U+Carry=10...
  
  By comparing these both 2nd columns,we get E=2,u=7,H=3,R=1..from here u can get the answer
• 10 years agoHelpfull: Yes(4) No(0)
• 345
  *876
  ______
  2070
  2415
  2760
  ______
  302220
  
  Firs we try to look or 1 & 0 or obvious clues-->>
  Since U*T=XT (Ends with T) We check The possibilites where( U+T=1E ) and we get
  2 possibilities i.e --> (U=7,T=5 & U=6,T=8).
  'E' is at he end of the number it can't be 0 similary leaving all the end numbers we get three possiblities of '0' i.e(A,I,R), checking the same we get 'I' AS '0'
  Seing the pattern that 'T' multiplied with any number we get either 0/5 so T=5 and we get U AS 7.Substituting the numbers we get 'H' as 3 since E=2 AND U=7. Cross checking again we get all the digits.
• 10 years agoHelpfull: Yes(1) No(0)
• Consider U*T=T and U+T=E... lets go through the assumption.... probably E can not be larger values.
  So consider E
• 11 years agoHelpfull: Yes(0) No(1)
• Consider U*T=T and U+T=E... lets go through the assumption.... probably E can not be larger values.
  So consider E
• 11 years agoHelpfull: Yes(0) No(1)
• Consider U*T=T and U+T=E... lets go through the assumption.... probably E can not be larger values.
  So consider E
• 11 years agoHelpfull: Yes(0) No(2)
• 345
  * 876
  --------
  302220
  --------
  Consider U*T=T and U+T=E... lets go through the assumption.... probably E can not be larger values.So consider E C=8.
  
• 11 years agoHelpfull: Yes(0) No(1)
• t*u=t
  hence t is 5... nd multiple of 5 is 5 nd 0 hence i=0
  this will help for further solution :)
  345*876
• 10 years agoHelpfull: Yes(0) No(1)
• Now see 3rd column from first ..E+A+P=10+E...which implies A+P=10..see all the combinations for 10..
  
  (1,9),(2,8),(3,7),(4,6)..only 4,6 satisfy..hence A=4,P=6 ...hence solved
• 10 years agoHelpfull: Yes(0) No(0)
• What does this question really mean???
• 8 years agoHelpfull: Yes(0) No(0)