Q. FOG + FOG + FOG + FOG = 1456.
If F,O and G are digits in a three-digit number in the preceding equation the F + O + G = ?

• given,FOG + FOG + FOG + FOG = 1456
  4(FOG)=1456
  =>FOG=364
  Face value of F is:3
  Face value of O is:6
  Face value of G is:4
  so F+O+G=3+6+4=13
• 11 years agoHelpfull: Yes(78) No(0)
• fog's are 4 ,
  so,1456/4=364,
  3+6+4=13
  
• 11 years agoHelpfull: Yes(8) No(0)
• FOG+FOG+FOG+FOG=1456
  4FOG=1456
  FOG=364
  F+O+G=13
• 10 years agoHelpfull: Yes(4) No(0)
• FOG+FOG+FOG+FOG=1456
  4FOG=1456
  FOG=1456/4=364
  so F+O+G=3+6+4=13
• 11 years agoHelpfull: Yes(1) No(0)
• f+o+g=13
  as f=3;o=6;g=4
  becoz 4(fog)=1456
  hence fog =364
• 11 years agoHelpfull: Yes(1) No(0)
• 13
  FOG +FOG +FOG +FOG =4(FOG)
  
  4(FOG)=1456
  FOG=1456/4
  FOG=364
  F=3
  O=6
  G=4
  F+O+G=3+6+4
  F+O+G=13
• 10 years agoHelpfull: Yes(1) No(0)
• FOG*4=1456
  FOG=1456/4
  FOG=364
  Thats why
  F+O+G=3+6+4
  Ans=13
• 10 years agoHelpfull: Yes(1) No(0)
• 13;
  4*FOG=1456;
  FOG=364;
  so,
  F+O+G=3+4+6;
  which equals 13.
• 10 years agoHelpfull: Yes(1) No(0)
• 364+364+364+364=1456
• 11 years agoHelpfull: Yes(0) No(2)
• 13 will be the answer
• 8 years agoHelpfull: Yes(0) No(0)
• 4 times of FOG is 1456 1 time of FOG is 364 THEN F+O+G is 3+6+4=13
• 8 years agoHelpfull: Yes(0) No(0)