Q. A student starts at the year 2011 and counts backwards, 7 at a time, giving the sequence of years: 2011, 2004, 1997, ...

A year which she will count is

• It backward by 7 so 2011/7 =287 & remainder will be 2 & it is greater than 0
  or when we 287*7=2009 then 2011-2009=2 so she will count upto 2
• 10 years agoHelpfull: Yes(17) No(2)
• actually wat s de question here ? wat do we need to find ?
• 10 years agoHelpfull: Yes(7) No(0)
• 1990 Because there is a 7 year gap in between.The years are given at an interval of 7 years.
  
• 10 years agoHelpfull: Yes(2) No(2)
• 2 year........
  
• 10 years agoHelpfull: Yes(1) No(0)
• a+(n-1)d=l here a = 2011,d=-7 so solving this max value of n is 287 and the last year is 3
• 10 years agoHelpfull: Yes(1) No(2)
• up to last year is 3...........
• 10 years agoHelpfull: Yes(0) No(1)
• The answer should be 116
• 10 years agoHelpfull: Yes(0) No(1)
• 1990
  1997-7=1990
• 10 years agoHelpfull: Yes(0) No(0)
• 1997-7=1990
• 10 years agoHelpfull: Yes(0) No(0)
• the question is not clear
  
• 10 years agoHelpfull: Yes(0) No(0)
• Answer is 2-year
• 10 years agoHelpfull: Yes(0) No(0)
• Ans : up to 2 years...student can count up to 286 times back
• 10 years agoHelpfull: Yes(0) No(0)
• can ne1 explain the ques clearly..
• 10 years agoHelpfull: Yes(0) No(0)
• arey bhai kehna jya
• 9 years agoHelpfull: Yes(0) No(0)