Q. Among which of the following p is greater than q?

Option
a) (0.9^p)=(0.9^q)
b) (0.9^p)=(0.92^q)
c) 0.9*p> 0.9q
d) 9*P>9*Q

• b is the right answer.
  Base value increases hence raised power must be reduced in right side.
  
• 11 years agoHelpfull: Yes(17) No(4)
• if we check option b, p*log0.9 = q*log .92
  p/q = .79 means p=.79q , so b cant be the answer....
  only option d is correct.
• 11 years agoHelpfull: Yes(13) No(0)
• b,c,d..
  c,d it is clear but in b to make 90^p=92^q p must be greater than q
• 11 years agoHelpfull: Yes(2) No(1)
• thimk its b because in both c and d dividing both sides with the respective co-efficients would give me p>q
• 11 years agoHelpfull: Yes(1) No(0)
• Why d is not correct...
  bcoz base is same and its greater than 1
  So p>q
• 11 years agoHelpfull: Yes(1) No(0)
• ans is b
  applying logarithm on both side
  ln(0.9^p) = ln(0.92^q)
  -0.105p = -0.083
  p = 0.79q
• 11 years agoHelpfull: Yes(1) No(3)
• c and d
  bacause of sign
• 11 years agoHelpfull: Yes(1) No(1)
• Higher power of any number which is between 0 and 1 leads to less value. Suppose .92^2=.8464 ,.92^1=.92 and .92^3=.778688. So for option b p
• 11 years agoHelpfull: Yes(1) No(0)
• 9p>9q
  so, p>q
• 11 years agoHelpfull: Yes(1) No(0)
• Answer is D
• 10 years agoHelpfull: Yes(1) No(0)
• the correct answer is d...
• 10 years agoHelpfull: Yes(1) No(1)
• a cannot be the ans bcoz p & q has to be equal,the question demands p>q. b cannot be the ans bcoz if p is increased 0.9^p decreases and is q is decreased 0.92^q increases.therefore both cannot be equal. The ans is c bcoz if we divide both sides by 0.9 by the rules of inequality, p>q..therefore c is the right ans.
• 11 years agoHelpfull: Yes(0) No(5)
• B is the right answer
  
• 11 years agoHelpfull: Yes(0) No(0)
• ans c,
  a is not the correct answer, in b if we appply logarithm on both sides then we get p =0.79*q so b is wrong, in d they given P (capital P not small p)and Q (captial Q not small q), so answer is c.
• 11 years agoHelpfull: Yes(0) No(1)
• C IS CORRECT BECUZ IT IS ONLY OPTION IN WHICH p>q WHILE IN OTHER EITHER BOTH ARE EQUAL OR CAPITAL P WHHICH IS NOT p
• 10 years agoHelpfull: Yes(0) No(0)