Elitmus
Exam
Numerical Ability
LCM and HCF
Q. What will be the least possible number of planks, if the three pieces of timber 42m,49m,63m long have to be divided into planks of same length?
Options
a) 7
b) 8
c) 22
d) None of these
Read Solution (Total 16)
-
- HCF of 42,49,63 is 7
so for 42 there will be 42/7=6
from 49 there will be 49/7=7
from 63 there will be 63/7=9
total no of planks 6+7+9=22 ans - 11 years agoHelpfull: Yes(43) No(0)
- @anitha yes least possible lenght og each plank is 7...question is number of planks divide 42,49,63 by 7 and add total 22 ..
- 11 years agoHelpfull: Yes(4) No(0)
- the possible length of planks that can be cut from three pieces of timber is the HCF of given lengths i.e. 7
so from first piece 42/7= 6 planks
and 49/7= 7 planks
63/7= 9 planks
so total= 6+9+7= 22 - 10 years agoHelpfull: Yes(1) No(1)
- Ans is 22... 42/7=6
49/7=7
63/7=9
6+7+9=22 (ans) - 9 years agoHelpfull: Yes(1) No(0)
- Ans is 7
We should have to see the hcf of these numbers 42,49,63
- 11 years agoHelpfull: Yes(0) No(1)
- 7
hcf of 42,49,63
i.e common is 7
- 11 years agoHelpfull: Yes(0) No(2)
- a) 7 (H.C.F of 42,49,63)
- 10 years agoHelpfull: Yes(0) No(1)
- we r going to find no of pieces of planks
so least possible length of each plank cut from three timber is = hcf(42,49,63)
and number of planks=(42+49+63)/7=22(ans) - 10 years agoHelpfull: Yes(0) No(0)
- 7 is the right ans. because hcf of 42,49,63i=7
- 10 years agoHelpfull: Yes(0) No(1)
- 7 is the right ans. because hcf of 42,49,63i=7
- 10 years agoHelpfull: Yes(0) No(1)
- HCF(42,49,63)=7
least length vl be 7...
no of pranks will be 42/7=6
49/7=7
63/7=9
so in total it vl be= 6+7+9=22 - 9 years agoHelpfull: Yes(0) No(0)
- HCF of 42,49,63 is 7.
(We find HCF because logs are equal sizes and we have to find the least possible number of planks.)
Number of planks=(42/7)+(49/7)+(63/7)=22
- 9 years agoHelpfull: Yes(0) No(0)
- Take HCF of 42,49, and 63, it will comes 7. All the pieces must be of size 7m. So total no of pieces =22
- 9 years agoHelpfull: Yes(0) No(0)
- 22
take HCF of these pieces that is 7 and
divide all pieces by 7 and sum all
42/7+49/7+63/7=22 - 6 years agoHelpfull: Yes(0) No(0)
- Ans is 22
Hcf=7
So,
42/7=6
49/7=7
63/7=9
6+7+9=22 - 2 years agoHelpfull: Yes(0) No(0)
- a)7
HCF of 42,49,63 is 7 - 2 years agoHelpfull: Yes(0) No(0)
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