Elitmus
Exam
Numerical Ability
Number System
Q. Find the no of divisor 1080 excluding the divisor which are perfect square?
Option
a) 28
b) 29
c) 30
d) 31
Read Solution (Total 6)
-
- no of divisors of 1080=2^3*5^1*3^3
then no of factors = 4*2*4=32
excluding perfect square factors=(2^0+2^2)(3^0+3^2)(5^0)=2*2*1=4
so ans=32-4=28 i.e. a - 11 years agoHelpfull: Yes(28) No(2)
- 28 is the answer
(2^0+2^1+2^2+2^3)(3^0+3^1+3^2+3^3)(5^0+5^1)
2^0.3^0.5^0=1
2^2=4,
3^2=9,
2^2.3^2=36
total number of factors
32
32-4=28 factors
- 11 years agoHelpfull: Yes(14) No(2)
- 1080=2^3 x 3^3 x 5^1
So, Number of divisors/factors = (3+1) x (3+1) x (1+1) = 32
Out of all the factors 1, 4(2^2), 9(3^3) and 36 (9 x 4) are perfect Squares.
So the answer is 32-4 = 28. - 10 years agoHelpfull: Yes(9) No(0)
- perform factorization
1080=(2^3)*(3^3)*5
no of factor=(2^0+2^1+2^2+2^3)*(3^0+3^1+3^2+3^3)*(5^0+5^1)
therfore no of factor which will divide 1080 are
4*4*2=32,from wich 4 and 9 are perfect square that divide 1080 therfore
32-2=30 is answer - 11 years agoHelpfull: Yes(2) No(10)
- @akash...how u calculae the no of factors...ie 32..explain
- 10 years agoHelpfull: Yes(1) No(1)
- brother.its ok if we get 91.but how? is it guess
- 10 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question