Q. Find the probability that a year chosen at random has 53 Mondays?

Option
a)5/28
b)3/28
c)1/28
d)3/28

Answer is -(a)
please explain this numerical

• probability of 53rd Monday in leap year=2/7
  Probability of 53rd Monday in normal year=1/7
  probability of leap year=1/4
  probablity of normal year=3/4
  required probability=((1/4)*(2/7))+((3/4)*(1/7))=5/28
• 11 years agoHelpfull: Yes(7) No(0)
• 1/2 * 1/2 * 5/7
• 11 years agoHelpfull: Yes(0) No(2)