Anyone knows the question asked on 22nd Dec, 2013.
Ques is like.
What will be the result, If (1/8)*(Some exp)*64;
Ans:Always even.
If anyone knows the question pls. post it.

• 1/8*(x^2 + y^2)*z^2=?.It can be even or odd,because x^2 is odd and y^2 is also odd.so odd + odd=even and z^2 is even.so whole numerator is even but if u divide even by 8 ans could be even or odd.
• 11 years agoHelpfull: Yes(8) No(4)
• this is not right question.. 1/8*(x^2 + Y^2)*z^2 where x and y always odd no.and z is even no.
  
  option a) can b fractional value
  b) always ood
  C) always even
  D) can b odd or even
  
• 11 years agoHelpfull: Yes(6) No(0)
• ope, Its not even or odd. because (1/8) * 64 = 8;
  So, multiplying any number by even no. is always even no.
• 11 years agoHelpfull: Yes(5) No(1)
• option d can b even or odd
  
• 11 years agoHelpfull: Yes(3) No(0)
• my answr was wrong it can b even or odd
  even when z=0,so 1/8*(x^2 + y^2)*z^2 =0
• 11 years agoHelpfull: Yes(3) No(0)
• yea mukul ..even div even = even or odd
• 11 years agoHelpfull: Yes(2) No(0)
• venkateah if the question is tat then ans will be even coz the exp will giv even number ..even div even= even
  venkatesh,k.arun can u plz post the cryptmul asked in xam if u hav given xam
• 11 years agoHelpfull: Yes(1) No(0)
• @venkatesh thank you for your question
• 11 years agoHelpfull: Yes(0) No(0)
• Its pleasure mr. arun Whether the ans is correct or incorrect?
• 11 years agoHelpfull: Yes(0) No(0)
• @ N ARUN:
  C O W *
  O N E
  --------
  N N R C
  O O V R-
  D E C D--
  -----------
  W O R O N C
  ------------
  AnS:743*469
  
• 11 years agoHelpfull: Yes(0) No(1)
• @venkatesh:
  Do you know the exact question. i.e. they have asked what is the remainder? or what is the value?
• 11 years agoHelpfull: Yes(0) No(0)
• yes MUKUL, Yu are ryt...
  but I just got that wrong.
• 11 years agoHelpfull: Yes(0) No(0)
• 
  @ Arun : tats the exact question and options. they dint ask value or remainder..
  
• 11 years agoHelpfull: Yes(0) No(0)
• always even
  even/8---->we cant break the odd multiple of 8 in the given format.
  e.g 0dd multiple of 8 r 8*1,8*3,8*5,8*7,8*9
  so in each case either x^2+y^2=8 and z^2=1,3,5... or x^2+y^2=1,3,5 and z^2=8
  which is not possible in any case.answer will be the even multiple of 8 only.
• 11 years agoHelpfull: Yes(0) No(3)
• @venkatesh: ok.. thanks..
• 11 years agoHelpfull: Yes(0) No(0)
• @RAVI: cant get your answer yaar.
  Ans can be 'even or odd' only na..
• 11 years agoHelpfull: Yes(0) No(0)
• answer= always even
• 11 years agoHelpfull: Yes(0) No(0)
• If w and x odd numbers,y and z even numbers then
  1/8[(w^2+x^2)*(y^2+z^2)]
  A.always odd
  B.always even
  C.may be both
  D.not an interger
  Ans:
  Let,
  w = 1(odd), x = 3(odd)
  y = 2(even), z=4(even)
  we get
  1/8* { ( 1 + 9 ) ( 4 +16 ) }
  1/8 * { 10 * 20 } = 25 [which is odd]
  
  now,
  If we take
  w = 1(odd), x = 3(odd)
  y = 12(even), z = 20(even)
  we get,
  1/8 * { ( 1 + 9 ) ( 144 + 400 ) }
  1/8 * { (10) (544) } = 680 [which is even]
  
  The value can be even and can be odd.
  So, the ans is C.
• 9 years agoHelpfull: Yes(0) No(0)
• @Avijit .. What is the sense of posting your question and answer here in comment section?
• 2 years agoHelpfull: Yes(0) No(0)