Q. If anybody remember this question plz give ans and make me correct question if i typed it wrong, If n,o,p are in A.P. and a,b,c are in G.P. then (p-o)log a +(n-p) log b + (o-n) log c equal to..

Option
a) (p-o) log c^4
b) (p-o) log abc
c) 1
d) 0

• since a,b,c r in gp.
  therfor: b^2=ac;
  and 2o=p+n or o-n=p-o=k;
  
  using above:
  kloga+(n-p)logb+klogc=k(loga*c)+(n-p)logb=klogb^2+(n-p)logb=2klogb+(n-p)logb
  now logb common :
  
  logb(2k+(n-p))=logb(2(p-o)+(n-p))=logb(2p-2o+n-p)=logb(p+n-2o)=logb(2o-2o)=logb*0= 0
• 10 years agoHelpfull: Yes(33) No(0)
• we have,o-n=p-o
  and b^2=ac
  loga^(p-o)+logb^(n-p)+logc^(o-n)=log(a^(p-o)*b^(n-p)c^(o-n)
  =log(ac/b^2)^o-n=Log(1)^o-n=0
• 10 years agoHelpfull: Yes(3) No(0)
• the answer is 0.
• 10 years agoHelpfull: Yes(0) No(0)
• 0
  is the answer
• 10 years agoHelpfull: Yes(0) No(0)
• it should be 14
• 10 years agoHelpfull: Yes(0) No(3)