Q. How many way ALLAHABAD can b arranged taking 4 letter at a time. Meaningless also allowed.

• ALLAHABAD=9.......4 combination...
  9C4= (9*8*7*6)/(4*3*2*1)=126
• 10 years agoHelpfull: Yes(1) No(4)
• there will be 6 cases:
  when all the four letters are different,
  when there are 2 a
  when there are 3 a
  when there are 4 a
  when there are 2 l
  when there are 2 l and 2 a
  so the number of words formed= 5c4*4!+4c2*4!/2!+4c1*4!/3!+1+4c2*4!/2!+4!/2!*2!=279
• 10 years agoHelpfull: Yes(1) No(1)
• ANS: 378 (if repetitions are not allowed)
  Allahabad=9 letters out of which we select 4 letters so 9P4 and 2a ->2! , 2l->2!,again 2a->2!
  9P4/(2!2!2!)=378
• 10 years agoHelpfull: Yes(0) No(1)