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Maths Puzzle
Numerical Ability
Permutation and Combination
Q. How many way ALLAHABAD can b arranged taking 4 letter at a time. Meaningless also allowed.
Read Solution (Total 3)
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- ALLAHABAD=9.......4 combination...
9C4= (9*8*7*6)/(4*3*2*1)=126 - 11 years agoHelpfull: Yes(1) No(4)
- there will be 6 cases:
when all the four letters are different,
when there are 2 a
when there are 3 a
when there are 4 a
when there are 2 l
when there are 2 l and 2 a
so the number of words formed= 5c4*4!+4c2*4!/2!+4c1*4!/3!+1+4c2*4!/2!+4!/2!*2!=279 - 11 years agoHelpfull: Yes(1) No(1)
- ANS: 378 (if repetitions are not allowed)
Allahabad=9 letters out of which we select 4 letters so 9P4 and 2a ->2! , 2l->2!,again 2a->2!
9P4/(2!2!2!)=378 - 11 years agoHelpfull: Yes(0) No(1)
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