Q. A number is like aabbc, where a>b>c eg 88331. If number is divided by 101, find the smallest remainder

• i think the answer will be 29..if the number is 99110
• 11 years agoHelpfull: Yes(11) No(2)
• according to the question take d largest 5 digit number i.e. 99887 and divide it by 101.. u get remainder 0
  if its not in option den subtract the number wid 101 and u'll get the smallest remainder.
• 11 years agoHelpfull: Yes(3) No(25)
• rem of(221100/101)=11
• 10 years agoHelpfull: Yes(3) No(6)
• since smallest remdr is asked ..so it is posaible wen given number is div by 101 ..hence 0 ...
  @ravi options u rember ?
• 11 years agoHelpfull: Yes(1) No(3)
• 99110 divided by 101 gives 29 remainder.. anyone calculated less than this remainder.. plz post.. i think this should be the ans.
• 10 years agoHelpfull: Yes(1) No(0)
• observing the given example i took 99887.when this is divided by 101 ,the remainder is 19.
• 10 years agoHelpfull: Yes(1) No(4)
• 29 is the correct answer
  
• 9 years agoHelpfull: Yes(1) No(0)
• 10,21,39 dnt knw exactly
• 11 years agoHelpfull: Yes(0) No(0)
• i got 39 by takin values .number is 99221 div 101
• 11 years agoHelpfull: Yes(0) No(2)
• @naveen y r u considering whole numbers ..we generally take natural numbers ?...as it is not mentioned to tkae asvwhile numbers
• 11 years agoHelpfull: Yes(0) No(0)
• we are considering the case when c is assigned lowest value i.e 0 and b=1 and c=2
  we get remainder 1 as we change the value of a=1 till the a get highest value i.e 7 we don't get any remainder higher then 1
• 11 years agoHelpfull: Yes(0) No(1)
• Answer is 0, as if
  a=11
  b=10
  c=0;
  then it satisfies the equation a>b>c
  and the number is 11 11 10 10 0 ( 111110100 )
  i.e. divisible by 101.
  only if the value of a, b and c can be of more than one digit, which isn't mentioned i think.
• 9 years agoHelpfull: Yes(0) No(3)