Q There is a cask full of milk E litres are drawn from the cask it is the filled with

Final conc= Initial conc* [1-(Amount replaced in each operation/total amount)]^no. of times operation is repeated
so 16/25=1*[1-(E/Capacity)]^2
=>4/5=1-[E/cap]
=>1-4/5=E/Cap
=>1/5=E/Cap
=>cap=5E(Ans)
10 years agoHelpfull: Yes(3) No(0)
4E
Formula:

X(1-E/X)^2=9/16
1-E/X=3/4
X=4E
11 years agoHelpfull: Yes(1) No(16)
can u explain ths can't understand
11 years agoHelpfull: Yes(0) No(0)
milk/water ratio is given 16:9
it would have 16/25 parts of milk and 9/25 parts of water.
now,let initial qty be x, take E liter of milk and replace it with water,if E liter is taken out,
the Qty of milk left =x-E
so the fraction of milk after one replacement =X-E/X,similarly
for second time also it would be X-E/X,So after two replacement milk would be
(X-E/X)^2=16:25(GIVEN)
solve from here..
main point to understand is that,we are taking about milk left/original qty.
11 years agoHelpfull: Yes(0) No(0)
question is There is a cask full of milk. E litres are drawn from the cask, it is the filled with water. This process is repeated until the ratio of milk to water in the cask is 16:9. What is the capacity of cask in litres.
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there is a two mixed series.
1st one- 8,14(8+6),20(14+6) i.e 6+ in every csr.
2nd one- 3,6(3+3),*(i.e it will be 6+3=9)
so its 9
10 years agoHelpfull: Yes(0) No(0)

Q. There is a cask full of milk. E litres are drawn from the cask, it is the filled with water. This process is repeated. Now the ratio of milk to water in the cask is 16:9. What is the capacity of cask in litres.