Q. Six blue balls are placed in 3 boxes. the probability of putting balls in the boxes in equal no is-

Option
a) 1/21
b) 1/8
c) 1/28
d) 1/7
please solve this example

• combinations for filling 6 balls
  i.e. sample space={(1,1,4),(1,4,1),(1,1,4),(2,2,2),{1,2,3),(2,3,1),(3,1,2)}
  Event of putting equal number of balls is(2,2,2)
  Probability=n(E)/n(S)=1/7.
• 10 years agoHelpfull: Yes(2) No(2)
• Prob of putting 6 (identical)balls in 3 box = 8C2 = 28 ways.....-> (n+r-1Cr-1)
  Prob of putting 2(Identical) balls each in 3 box can be done in 1 ways.
  Hence total prob = 1/28.
• 7 years agoHelpfull: Yes(1) No(0)
• Ans is c)1/28
• 9 years agoHelpfull: Yes(0) No(0)
• how come its 1/28 ?
  
• 8 years agoHelpfull: Yes(0) No(1)
• the above solution is correct if the 0 condition is excluded.
• 7 years agoHelpfull: Yes(0) No(0)