Q. Mr and Mrs A are opposite to each other.The distance between Mr A and Mrs A are 120 km.The speed of Mr A and Mrs A are 30 kmph, 10 kmph respectively.one Bee is running between Mr A nose to Mrs A nose and returning back to Mr A nose.The speed of Bee is 60 kmph. Then How far Bee traveled?

• 30x+10X=120
  X= 3 hrs
  speed of bee=60kmph
  distance traveled by bee=speed * time taken=60*3=180km
  
• 10 years agoHelpfull: Yes(15) No(5)
• 137.1kms....and 2.285hrs
  
  suppose Mr A and Bee are in left side...
  Now , They srart to travel
  After, 1.714 hrs Bee and Mrs A meet and Bee travel 102.86 km and Mrs A travel 17.14 km and same time Mr A travel left to right is 51.429 km ...
  So, We are taking 102.86 km which is travel by Bee...
  
  Now, Distance between Mr A and See is 51.429 km...and they are now opposite to each other....
  so they meet after 0.5714 hrs ...
  
  So, Total time is 1.714hrs and 0.5714 is 2.285 hrs...
  
  but speed of Bee is 60kmph, total distanc travel by Bee is 2.285*60
  137.1 kms
• 10 years agoHelpfull: Yes(5) No(6)
• 120-(30*T+10*T)=60*T
  120=100T
  T=1.2H
  DISTANCE=1.2*60=72KM
• 10 years agoHelpfull: Yes(1) No(6)
• I second Divya Murugesh but the case will be Mr and Mrs A are opposite to each other at same point and all three Mr A, Mrs A and Bee started moving from there with respective speed making distance of 120km between Mr A and Mrs A. Then, equation will be 30X+10X =120.
• 10 years agoHelpfull: Yes(0) No(4)
• they both will meet in 3 hrs. therefore 3*60=180
  Ans:180km
• 9 years agoHelpfull: Yes(0) No(2)