Q. How many numbers of 5 digits can be formed with the digits 0, 1, 2, 3, 4, 6 & 8 with no digit being repeated in the same number?

Option
A) 2170
B) 2160
C) 4396
D) 4500

• Ans: 2160
  As we have 5 digits.. and having no repeation..
  For the first digit can't be "0".. so, possibilities are 6..
  for the second digit the possibilities are 6 including "0" also..
  for the third digit there are 5 possibilities
  for the fourth digit 4 possibilities
  for the fifth digit 3 possibilities..
  so, total no.of numbers can form is 6*6*5*4*3=2160
• 11 years agoHelpfull: Yes(19) No(0)
• 5 digits will be -,-,-,-,-.
  first blank can occupy "6" ways i.e.,(1,2,3,4,6,8) but not '0' because we can't form 5 digits with starting 0
  2nd blank occupy "6"ways (either 0 or 1 or 2 or 3 or 4 or 6 or 8) but we shudnt take again first digit
  similarly 3rd in "5"ways,
  4th blank in "4" ways,
  5th blank in "3" ways.
  total = 6*6*5*4*3 = 2160
• 11 years agoHelpfull: Yes(3) No(0)
• 6*6c4*4!=2160
  option b
• 11 years agoHelpfull: Yes(0) No(0)
• 6C1*6P4= 2160.......
  
• 11 years agoHelpfull: Yes(0) No(1)
• 6*6*5*4*3=2160
• 11 years agoHelpfull: Yes(0) No(0)
• 6*6*5*4*3 = 2160
  
• 11 years agoHelpfull: Yes(0) No(0)
• B:6*6*5*4*3=2160
  
• 11 years agoHelpfull: Yes(0) No(0)
• _ _ _ _ _
  | | | | |
  6 6 5 4 3
  no.of ways=6*6*5*4*3=2160...
• 10 years agoHelpfull: Yes(0) No(0)