Q. Petrol and kerosene are mixed in vessel A in the ratio of 4:5 and in vessel B in the ratio of 9:4. In what ratio should these be taken out from both the vessels so as to make a mixture in which the ratio of petrol to kerosene will be 1:1?

• lets say x is the amount of mixture in A and y is the amount of mixture in the vessel B.. then we get the following equation x*(4/9)+y*(9/13)=1 and x*(5/9)+y*(4/13)=1 where x*(4/4+5) is the amount of kerosene in A
  y*(9/4+9) is the amount of kerosene in A
  so solving both equation we get x=405 and y=116
• 10 years agoHelpfull: Yes(4) No(1)
• let cp of petrol be Rs.1 per litre
  petrol in 1 litre mixture of A=4/9 ; cp of 1 litre mix. A=4/9
  petrol in 1 litre mixture of B=9/13; cp of 1 litre mix. B=9/13
  petrol in 1 litre mixture of C=1/2 ; mean price=1/2
  by the alligation rule
  cp of 1 litre mix A cp of 1 litre mix in B
  4/9 9/13
  /
  -------- 1/2 -------------
  /
  5/26 -1/18
  
  5/26 = 1/18 => 45:13
  
  so ans is 45:13
• 9 years agoHelpfull: Yes(4) No(0)
• 405:116,take x lit from a and y lit from b, x*4/9+y*9/13=1 and 5*x/9+4*y/13=1
  solv for x and y take ratio of x:y
• 10 years agoHelpfull: Yes(0) No(0)
• A- 4:5
  B- 9:4
  let result be X:Y
  4X+9Y=5X+4Y
  Solving This we get
  X:Y=5:1
• 7 years agoHelpfull: Yes(0) No(1)