Q. A contractor undertakes to build a wall in 50 days.He employs 50 men for the same. However,after 25 days he finds that the work is only 40% complete. How many more men need to be employed to complete the work 10 days before time?

• 75 men
  As 40% work by 50 men is completed in 25 days,
  The whole work can be completed in 25*100/40=125/2 days
  So 1 man, 1 day work=2/(125*50)=1/3125
  50 men,25 days work=25*2/125=2/5,
  The remaining work(=3/5) is to be completed by 50 men+ 'x' men in next 15 days (Total 40 days),
  So 15[(2/125)+(x*1/3125)]=3/5
  750+15x=1875, x=75
• 11 years agoHelpfull: Yes(2) No(0)