Q. A, B, C, D&E are having their birthdays on consecutive days of the week not ecessarily in the same order. A 's birthday comes before G's as many days as B's birthday comes after E's. D is older than E by 2 days. This time G's birthday came on wednesday. Then find the day of each of their birthdays?

• order may be as follows...
  DAEGB
  D:SUN
  A:MON
  E: TUE
  G: WED
  B: THU
  
• 11 years agoHelpfull: Yes(16) No(2)
• given, A 's birthday comes before G's as many days as B's birthday comes after E's
  from this, A _ G & D _ E and D is older than E by 2 days means in between D and E one person is there,, from these, D A E G B.. will be the correct sequence. It is satisfying all the above mentioned conditions.
  So , D A E G B
  D - Sunday
  A _ Monday
  E _ Tuesday
  G _ Wednesday
  B _ Thursday
• 11 years agoHelpfull: Yes(6) No(1)
• Answer:D,A,G,E,B
  D-Monday
  A-tuesday
  G-Wednesday
  E-Thursday
  B-Friday
• 11 years agoHelpfull: Yes(2) No(3)
• where is G?
  
• 11 years agoHelpfull: Yes(0) No(1)
• cosider G as C then answer is
  GBDAE
  G - wednesday
  B - thursday
  D - friday
  A - saturday
  E - sunday
  E
• 11 years agoHelpfull: Yes(0) No(2)
• can you please explain how you got D A G E B
  
• 11 years agoHelpfull: Yes(0) No(0)
• d-sun
  a-mon
  e-tue
  g-wed
  b-thu
• 10 years agoHelpfull: Yes(0) No(0)