Q. Father says my son is five times older than my daughter. my wife is 5 times older that my son. I am twice old from my wife and altogether (sum of our ages) is equal to my mother's age and she is celebrating her 81 birthday. so what is my son's age?

• let daughter's age be x
  son's age= 5x
  wife's age=25x
  his age= 50 x
  sum= 81= x+5x+25x+50x
  hence, x=1
  now daughter's age is x=1
  sons' age is 5x=5
  son is 5 years old
• 10 years agoHelpfull: Yes(56) No(2)
• son's age is 5 years
  
• 10 years agoHelpfull: Yes(5) No(0)
• given that all ages together is mothers age so
  father+wife+daughter+son=81
  i.e..,f+w+d+s=81
  we know that sons age is 5 times the daughters age so s=5d then d=s/5
  now
  f+w+(s/5)+s=81
  wifes age is 5 times sons age so w=5s
  now
  f+(5s)+(s/5)+s=81
  we also know that fathers age is twice of wifes age so f=2w =>f=2(5s)=>10s
  now
  10s+5s+(s/5)+s=81
  16s+s/5=81
  81*s=81*5
  finally ans is s=5...
  
• 10 years agoHelpfull: Yes(4) No(0)
• s=5d, w=5s=25d, f=2w=10s=50d
  50d+25d+5d+d=81
  thus, d=1
  hence, son's age= 5d=5
• 10 years agoHelpfull: Yes(4) No(0)
• lets son age is x
  daughter age is y
  wife age is z
  father age is a
  then
  x=5y
  z=5x
  a=2z
  altogether is
  x+y+z+a=81
  by substituting all
  we get 81y=81
  hence y=1
  so x=5(1)
  son's age is 5years
• 10 years agoHelpfull: Yes(2) No(0)
• Daughter's age=D
  son's age =5D
  mother's age=5*son's age=25D
  father's age=2*mother's age=50D
  But,total sum of the four person is 81;
  hence 50D+25D+5D+D=81
  hence son's age is 5
• 10 years agoHelpfull: Yes(1) No(0)
• daughter age=x
  son age =5x
  wife's age=5(5x)=25x
  father's age=5(25x)=50x
  x+5x+25x+50x=81
  x=1
  so,ans=5
  
• 10 years agoHelpfull: Yes(1) No(0)
• 5 YEARS
  S=SON,D=DAUGHTER,W=WIFE,I=HUSBAND
  S=5D
  W=25D
  I=50D
  D+5D+25D+50D=81
  D=1 THEN
  S=5 YEARS
• 9 years agoHelpfull: Yes(1) No(0)
• let daughter age =x .........5x+x+25x+50x=81,then x=1 so age of son is 5x=5*1=5
• 9 years agoHelpfull: Yes(1) No(0)
• age of son=5 years
• 10 years agoHelpfull: Yes(0) No(0)
• suppose daughters age=D
  THEN sons age S=5D
  wife age W=5s=5*5D=25D
  my AGE H =2*W= 50D
  NOW alltogether equals mothers age=81
  D+5D+25D+50D=81
  D=1,S=5D=5
  
  SONS AGE =5
• 10 years agoHelpfull: Yes(0) No(0)
• 25 will be answer...
• 10 years agoHelpfull: Yes(0) No(4)
• S=5D
  W=5S
  M=2W
  S+W+M=81
  RIGHT ALL AGES IN TERMS OF SON
  M=2W=2*5S=10S
  s+5S+10S=81
  16S=81
  S=5
• 10 years agoHelpfull: Yes(0) No(1)
• daughter=1 year
  son=1*5=5 years
  wife=5*5=25 years
  father=25*2=50 years
  sum=1+5+25+50=81 years
• 9 years agoHelpfull: Yes(0) No(0)
• Let the age of daughter be x
  Age of the son=5x,Wife's age=25x
  Father's age=50x
  According to question,
  50x+25x+5x+x=81
  Hence ,x=1
  Therefore, Son's age is 5 yrs.
• 9 years agoHelpfull: Yes(0) No(0)
• Son's age is 5.
  
  Let us assume
  daughter's age is x
  Son's age will be 5x
  Wife's age will be 5*5x = 25x
  Father's age will be 2*25x = 50x
  
  Sum(f,w,s,d) = age of mother (i.e.. 81)
  x+5x+25x+50x = 81
  81x = 81
  X = 1(daughter's age)
  Then sons will be 5*1=5
• 3 years agoHelpfull: Yes(0) No(0)