Q. In a certain office, 1/3 of the workers are women, 1/2 of the women are married and 1/3 of the married women have children. If 3/4th of the men are married and 2/3rd of the married men have children, what part of workers are without children?

• ans is : 11/18
• 11 years agoHelpfull: Yes(20) No(2)
• women=p/3(if total no of workers=p) & men=2p/3
  married womn=(p/3)*0.5=p/6 & marrd mn=(2p/3)*(3/4)=p/2
  wmn with chld=(p/6)*(1/3)=p/18 & mn with chld=(p/2)*(2/3)=p/3
  without chld=p-(p/18+p/3)=11p/18
  
  solved by :- SUBHRAJIT MITRA
  therefore ans is=11/18
• 11 years agoHelpfull: Yes(15) No(0)
• 5/18
  bcz totala workers be x:
  (1/3)x=women:
  so, (2x/3)=men:
  (x/6):married_women:(x/2):married men:
  (x/18):Women__childrn:(x/3):chill_men:
  so,(x/9):Not hv_childr(women) (x/6):Nt_hv_chil_men:
  so (x/9)+(x/6)=(5/18)x
• 11 years agoHelpfull: Yes(6) No(4)
• let total employees=90
  women=30,men=60
  married women having children=5
  women without children= 30-5=25
  married men having children=30
  men without children= 30
  so part of employees without children= (30+25)/90 = 11/18
• 11 years agoHelpfull: Yes(5) No(1)
• Here we want to know the part of workers that are without children. If we subtract the total workers from the workers that has children we can get the solution.
  let the total workers be x.
  total women workers = 1/3 of total workers
  = 1/3 of x = 1/3x
  total married women = total women workers / total married women
  = 1/3x / 1/2=1/6x
  total married women having children = total married women / total married women with children = 1/6x / 1/3 = 1/18x
  
  similarly calculate for married men with children = 1/3x
  Now workers without children= total workers - (women with children + men with children)
  x-(1/18x + 1/3 x)=11/18x
  Answer is 11/18
  
• 11 years agoHelpfull: Yes(3) No(0)
• women = 1/3 :: Men = 2/3
  Married women = 1/6 :: Married men = 1/2
  women have children = 1/18 :: Men have children = 1/3
  Part of workers without children = 1-(1/18+1/3) = 11/18
• 11 years agoHelpfull: Yes(3) No(0)
• consider total strength is x
  then women are x/3, married are x/6,in which have children x/18.
  rem 2x/3 are men,which x/2 are married,which 2x/6 have child.
  so people wthout chldren are x-(x/18)-(2x/6)=11x/18...ans is 11/18
• 11 years agoHelpfull: Yes(2) No(0)
• 7/18 part of workers are without children
• 11 years agoHelpfull: Yes(0) No(4)
• pls anyone explain the solution..
• 11 years agoHelpfull: Yes(0) No(0)
• @ganpati why 5/18 explain
  
• 11 years agoHelpfull: Yes(0) No(0)
• plz anyone send me the latest elitmus n infosys question papers.
• 11 years agoHelpfull: Yes(0) No(0)
• @SHOAIB how 11/18 would u plz explain???
• 11 years agoHelpfull: Yes(0) No(0)
• its : 11/18
• 11 years agoHelpfull: Yes(0) No(0)
• 11/18 is the correct answer
• 11 years agoHelpfull: Yes(0) No(0)
• ans is:-11/18
• 11 years agoHelpfull: Yes(0) No(0)
• suppose total employee=90 ,women=90*1/3=30,married=30*1/2=15,children=15*1/3=5
  men employee=90-30=60,married=60*3/4=45,children=45*2/3=30
  so total employee with children=30+5=35
  employee wdout children=90-35=55
  part of workers wdout children=55/90=11/18
• 11 years agoHelpfull: Yes(0) No(0)