TCS
Company
Numerical Ability
Percentage
Q. If A speaks the truth 20% of the times, B speaks the truth 40% of the times. What is the probability that they tell the truth at the same time.
Read Solution (Total 7)
-
- P(A)= 20/100=1/5
P(B) = 40/100= 2/5
P(A and B)
=1/5* 2/5
=2/25 ans. - 11 years agoHelpfull: Yes(41) No(1)
- 8/100
as 20/100*40/100. - 11 years agoHelpfull: Yes(4) No(4)
- p(a and b )= p(a)*p(b) iff a and b are independent events.. therefore here p(a and b)= p(a)*p(b)=(1/5*2/5)=2/25.
- 10 years agoHelpfull: Yes(3) No(0)
- A speaks truth A(T)=20/100=1/5 and A(not speaking truth)=4/5
similarly B(T)=2/5 and B(not speaking truth)=3/5
probability that they tell the truth at the same time= 1-(4/5*3/5)=13/25
- 10 years agoHelpfull: Yes(2) No(2)
- A speaks truth A(T)=20/100=1/5 and A(not speaking truth)=4/5
similarly B(T)=2/5 and B(not speaking truth)=3/5
probability that they tell the truth at the same time=(1/5*3/5)+(2/5*4/5)=11/25
- 10 years agoHelpfull: Yes(1) No(0)
- So is it 3/5 ?
- 11 years agoHelpfull: Yes(0) No(7)
- 2/25 is the probability
- 10 years agoHelpfull: Yes(0) No(0)
TCS Other Question