IBM
Company
Logical Reasoning
Seating Arrangement
Q. What is the next number of the following sequences
1. 38,36,76,35,114,34,..
2. 18,6,24,4,30,10,12,2,6,...
3. 1.25,3.71,1.50,1,8.1,1.75,-1,9.1,2.00,...
4.9,3,6,21,9,12,33,15,18,45,21,24,...
Read Solution (Total 23)
-
- 1)
38,36,76,35,114,34,..
38*1=38
38*2=76
38*3=114
38*4=152
so ans is 152
2)
18,6,24,4,30,10,12,2,6,...
18/6=3
24/46=6
30/10=3
12/2=6
6/X=3
put x is 2
so 6/2=3
hence ans is 2
4)
9,3,6,21,9,12,33,15,18,45,21,24,...
4th no - 1st no =>21-9=12
7th no - 4th no =>33-21=12
10th no - 7th no =>45-33=12
13th no -10th no =>X-45=12
put x is 57
so 57-45=12
so ans is 57
- 11 years agoHelpfull: Yes(26) No(0)
- 2. ans=2
6*3=18
4*6=24
10*3=30
2*6=12
so
2*3=6 - 11 years agoHelpfull: Yes(14) No(7)
- 3.i think the series is 1.25,3,7.1,1.50,1,8.1,1.75,-1,9.1,2.00
then ans is -3,10.1,2.25 - 11 years agoHelpfull: Yes(13) No(4)
- 1.next no is 152 as at odd places table of 38 goes on... so answer is 38 * 4= 152
- 11 years agoHelpfull: Yes(6) No(0)
- 4. 9 3 6
21 9 12
33 15 18
45 21 24
57
answer=57 - 11 years agoHelpfull: Yes(6) No(0)
- 4.)(9,3,6),(21,9,12),(33,15,18),(45,21,24),..
9->3+6= 1st term-> 2nd term + 3rd term
tis applies to each grp
now for the first term of 5th grp
9=3*3
21=3*7
33=3*11
45=3*15
57=3*19
so the next term is 57
- 11 years agoHelpfull: Yes(5) No(0)
- 4.ans=57
3rd term(6)+2nd term(3)=1st term(9)
1st term(9)+12=21
and so on...45+12=57 - 11 years agoHelpfull: Yes(2) No(0)
- 4. 9=3+6(3*1=3,3*2=6)
21=9+12(3*3=9,3*4=12)
33=15+18(3*5=15,3*6=18)
45=21+24(3*7=21,3*8=24)
57=27+30(3*9=27,3*10=30) - 10 years agoHelpfull: Yes(2) No(0)
- 1.38+36=74+2=76
76+35=111+3=114
114+34=148+4=152 - 11 years agoHelpfull: Yes(1) No(0)
- 3. 3,2,1,0,-1,-2,-3
ans is -3.
2nd=3 5th=1 8th=-1 11th =-3 - 11 years agoHelpfull: Yes(1) No(0)
- 3.)question no 3 is wrong.. it should be" 1.25, 3, 7.1, 1.50, 1, 8.1, 1.75, -1, 9.1 ,2.00"
answer is -3.
1.25 1.50 1.75 2.00 (x+0.25)
3 1 -1 -3 (x-2)
7.1 8.1 9.1 (x+1.0) - 10 years agoHelpfull: Yes(1) No(0)
- 3. sequence: 1.25, 3, 7.1, 1.50, 1, 8.1, 1.75, -1, 9.1, 2.00, ....
!st series: 1.25, 1.50, 1.75, 2.00, ....
2nd series: 3, 1, -1, ....
3rd series: 7.1, 8.1, 9.1, ....
so the answer is: -3, 10.1, 2.25 - 9 years agoHelpfull: Yes(1) No(1)
- 36, 35, 34 difference of 1.
36, 76, 114 difference of 38.
114+38=152 - 9 years agoHelpfull: Yes(1) No(0)
- 4, ans:57...
- 11 years agoHelpfull: Yes(0) No(0)
- there are 2 series
36 35 34.....and
38*2=76
38*3=114
So the next number in the series should be 38*4=144...after that the next number shd be 33
- 11 years agoHelpfull: Yes(0) No(0)
- 1. split the serious
38,76,114,152..(add 38) and 36,35,34,33
ans=152,33 - 11 years agoHelpfull: Yes(0) No(0)
- 36,35,34 are in series
38+38=76,76+38=114,114+38=152
- 11 years agoHelpfull: Yes(0) No(0)
- 4)for every 1st,4th,7th.. posotions
9+12=21
21+12=33..
for 2nd,5th..postions
3*1=3
3*3=9
3*5=15....
for 3rd 6th..positions
3rd=1st-2nd
6th=4th=5th..
so and=
45+12=57
3*7=21
57-21=36
so series is 57,21,36
- 11 years agoHelpfull: Yes(0) No(0)
- 3. 3,2,1,0,-1,-2,-3
ans is -3.
2nd=3 5th=1 8th=-1 11th =-3 - 11 years agoHelpfull: Yes(0) No(0)
- 1) 152
2) 2
3) 0.01
4) series (63,33,30) - 11 years agoHelpfull: Yes(0) No(0)
- 4. 9,3,6,21,9,12,33,15,18,45,21,24,...
9-3=6
21-9=12
33-15=18
45-21=24
So 3rd place series s lyk -> 6,12,18,24
Nd d 2nd place s lyk alternating multiples of 3-> 3,9,15,21
So d next series s X-27=30
So X=57
- 11 years agoHelpfull: Yes(0) No(0)
- 1at no- 3*3
4th no= 3*7
7th no= 3*11
11th no=3*15
13th no=missing no=3*19=57 - 11 years agoHelpfull: Yes(0) No(1)
- 2> (18/6)(24/4)(30/10)(12/2)(6/2)(6/1)
3 6 3 6 3
so ans be 6 nd 1. - 8 years agoHelpfull: Yes(0) No(0)
IBM Other Question
Q. What is the next number of the following sequences
1. 12,3,15,14,6,19,16,9,23,18,12,...
2. -15,-14,34,32,42,39,58,54,61
Q. What is the next number of the following sequence
1. 1/2,5/4,2,11/4,7/2,..
2. 0.5,1.25,2,2.75,3.5,.
3. 5,50,10,40,15,30,20,20,...
4. 11,17,-6,-13,24,30,-19,-26,20,...