1. There were 9 men and children.
2. There were 2 more women than children.
3. The number of different man-woman couples possible was 24. Note that if there were 7 men and 5 women, then there would have been 35 man-woman couples possible.

Also, of the three groups - men, women and children - at the party:
4. There were 4 of one group.
5. There were 6 of one group.
6. There were 8 of one group.
Exactly one of the above 6 statements is false.

Can you tell which one is false? Also, how many men, women and children are there at the party

• Statement 4 is false. Men = 3 , Women = 8 , children = 6
  
• 11 years agoHelpfull: Yes(18) No(4)
• 1)M+C=9
  2)W=C+2
  ==>C=W-2
  sub C=W-2 in (1)
  M+W-2=9
  M+W=11
  3)M*W=24
  possible value for M&W that satisfies M+W=11 & M*W=24 is 8M 3W & 3M 8W
  by using these 2 C can be 6 or 1
  so possibility is 8M 3W 1C & 3M 8W 6C
  so statement (4) says 4 in one group but it is not possible
  so ans is (4)
• 10 years agoHelpfull: Yes(15) No(0)
• statement 4 is incorrect
  men , women , children can be= 3,8,6 or 8,3,1
  
  
• 11 years agoHelpfull: Yes(3) No(2)
• first one is correct if the number of men=3 women=8 children=6
• 11 years agoHelpfull: Yes(2) No(4)
• option 3 is false as the question says that there are 9 men let the children be x and then verify options 4,5,6 there will be no chance of getting 24 as the total men are 9 and woman are 6 so 9c6 which gives us 84
• 11 years agoHelpfull: Yes(1) No(6)
• there are 3 men , 6 childern and 8 women ..
  4th statement is wrong.
• 11 years agoHelpfull: Yes(1) No(1)
• incase of 6 women and 4 children...men will be 5..then 6 ll br false..!!
  
• 11 years agoHelpfull: Yes(0) No(1)
• by using statements 1 2 and 3 we get two solutions(1.m=8,c=1,and w=3..2. m=3,c=6,w=8) hence statement 4 is false
• 10 years agoHelpfull: Yes(0) No(0)
• statment 5 is wrorng
  
• 10 years agoHelpfull: Yes(0) No(1)
• 3rd statement is false...
• 10 years agoHelpfull: Yes(0) No(1)