IBM
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Numerical Ability
Arithmetic
A clerk multiplied a number by ten when it should have been divided by ten.The ans he got was 100.what should the ans have been?
Read Solution (Total 6)
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- (56,89,33,21)(57,88,35,19)(60,85,30,x)
1st term:56,56+1,56+4
2nd term:89,89-1,89-4
==========================
3rd term:33,33+2,33-3
4th term:21,21-2,21+3
so Ans:24
(or)
56+89+33+21=199
57+88+35+19=199
60+85+30+x=199
so x=24
- 11 years agoHelpfull: Yes(38) No(7)
- see 56 ,57 ,60 means +1 ,+3
89 ,88,85 means -1,-3
33 ,35,30 means +2, -5
so 21 ,19,24 means -2,+5 - 11 years agoHelpfull: Yes(10) No(5)
- (56,89,33,21),(57,88,35,19),(60,85,30,x)
1st terms of brackets => 56 , 56 + 1 , 56 + 4
2nd terms of brackets => 89 , 89 - 1 , 89 - 4
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3rd terms of brackets => 33 , 33 + 2 , 33 - 3
4th terms of brackets => 21 , 21 - 2 , 21 + 3 = x
=> x = 24 - 11 years agoHelpfull: Yes(8) No(2)
- 56 57 60 +1 +3
89 88 85 -1 -3
33 35 30 +2 -5
21 19 14 +2 -5 - 11 years agoHelpfull: Yes(5) No(4)
- let the number be x, instead division clerk mutliplied by 10 so he got x*10=100
original value x=100/10=10;
the ans is 10/10=1 - 9 years agoHelpfull: Yes(4) No(0)
- Let the number be X,
Instead of dividing the number by 10, i.e.,X*10.
he got the result as 100,
so, (X*10)=100
X=100/10
X=10.
BUt he has to divide X by 10,
so, X/10=10/10=1.
obviously the answer is 1. - 9 years agoHelpfull: Yes(3) No(0)
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