Q. There are certain diamonds in a shop.
1. thief stole half of diamonds and 2 more.
2. thief stole half of remaining and 2 more
3. same as above
4. same as above.
5. came nothing was left for that.how many diamonds was there???

• answer=60
  let the total diamonds x.
  first person took x/2 and extra 2,
  so the remaining are (x/2)-2= let it be y,
  similarly , the second person took y/2 + 2, so remaining are y/2 -2.........
  after 4 similar attempts,the shop is left with 0 diamonds,
  so the final expression will be
  1/2*(1/2*(1/2*(x/2 -2)-2)-2)-2 =0
  from this x =60
  so, first person took 60/2 +2 =32
  2nd person took 28/2 +2 = 16
  3rd person took 12/2 +2 =8
  4th person took 4/2 +2 =4
  so........we are left with 0 diamonds in the shop..
• 11 years agoHelpfull: Yes(4) No(0)
• Let diamonds be X
  X/2 + 2 ,(X/2 - 2)/2 + 2 , 3x/8 +1/2+2 ,finally (x - ((3x-4)/2 + 2)) / 2 + 2 = 0(total)
  from this we get x=60...
  lets check
  60 are total coins...
  1.60 / 2 + 2 = 32 are stolen... 28 are remaing...
  2.28 /2 + 2 = 16 are stolen... 12 are remaining...
  3.12/2 + 2 = 8 are stolen.... 4 are remaining....
  4.4/2 + 2 = 4 are stolen.... 0 are remaing...
  so, it is 60.......
• 10 years agoHelpfull: Yes(0) No(0)
• the answer is 60.
• 7 years agoHelpfull: Yes(0) No(0)