Q. If a person having 1000 rs and he want to distribute this to his five children in the manner that each son having 20 rs more than the younger one , what will be the share of youngest child

• Assume first child (the youngest) get = x Rs.
  
  According to the question ;
  each son having 20 rs more than the younger one
  
  Second child will get = x + 20 Rs
  Third child will get = x + 20 + 20 = x + 40 Rs
  Forth child will get = x + 20 + 20 + 20 = x + 60 Rs
  Fifth child will get = x + 20 + 20 + 20 + 20 = x + 80 Rs
  
  Total amount they got = 1000 Rs
  
  x + (x+20) + (x+40) + (x+60) + (x+80) = 1000
  5x + 200 = 1000
  5x = 800
  x = 160 Rs.
  So the youngest child will get 160 rs
• 11 years agoHelpfull: Yes(32) No(1)
• amount of five children can be assumed as
  (x-2*20),(x-20),x,(x+20),(x+2*20)
  total amount=1000
  or (x-2*20)+(x-20)+x+(x+20)+(x+2*20)=1000
  or 5x=1000
  or 5x=1000
  or x=200
  share of youngest child=(x-40)=(200-40)=160
  
  
• 11 years agoHelpfull: Yes(13) No(5)
• suppose younger son get x rs then immediate elder brother will get x+20 and and his immediate elder brother will get x+40, similarly x+60 and x+80.
  and sum of all is 1000,so x+x+20+x+40+x+60+x+80=1000
  5x+200=1000
  5x=800
  x=160
  so ans is 160 that is share of yongest brother.
• 11 years agoHelpfull: Yes(1) No(1)
• 160,180,200,220,240
• 10 years agoHelpfull: Yes(1) No(1)
• Let younger one get x and he divided money into x, x + 20, x + 40, x + 60, x + 80.
  
  x + x + 20 + x + 40 + x + 60 + x + 80 = 1000
  5x + 200 = 1000
  5x = 800
  x= 160
  Younger one gets 160.
• 6 years agoHelpfull: Yes(1) No(0)
• x+(x+20)+(x+40)+(x+60)+(x+80)=1000
  x=160.
• 11 years agoHelpfull: Yes(0) No(2)
• its 120 ,because 1000 /5=200 ,200-80=120
• 7 years agoHelpfull: Yes(0) No(2)
• Given:
  The total amount of money = ₹1000.
  The father has 5 children.
  The amount of money each child gets increases by ₹20 for each successive child.
  We need to find the share of the youngest child.
  Let’s assume:
  The youngest child gets ₹
  𝑥
  x.
  The second youngest child will get ₹
  𝑥
  +
  20
  x+20.
  The third youngest child will get ₹
  𝑥
  +
  40
  x+40.
  The fourth child will get ₹
  𝑥
  +
  60
  x+60.
  The oldest child will get ₹
  𝑥
  +
  80
  x+80.
  Step 1: Set up the equation for the total amount distributed
  The total money is ₹1000. So, the sum of all the children's shares will be:
  
  𝑥
  +
  (
  𝑥
  +
  20
  )
  +
  (
  𝑥
  +
  40
  )
  +
  (
  𝑥
  +
  60
  )
  +
  (
  𝑥
  +
  80
  )
  =
  1000
  x+(x+20)+(x+40)+(x+60)+(x+80)=1000
  Step 2: Simplify the equation
  Now, simplify the left-hand side:
  
  5
  𝑥
  +
  20
  +
  40
  +
  60
  +
  80
  =
  1000
  5x+20+40+60+80=1000
  5
  𝑥
  +
  200
  =
  1000
  5x+200=1000
  Step 3: Solve for
  𝑥
  x
  Subtract 200 from both sides:
  
  5
  𝑥
  =
  800
  5x=800
  Now, divide by 5:
  
  𝑥
  =
  160
  x=160
• 15 Days agoHelpfull: Yes(0) No(0)