A contract on a construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs 200 for first day, Rs. 250 for second day, Rs. 300 for third day and so on. If the contractor pays Rs 27750 as penalty, find the number of days for which the construction work is delayed.

• 30
• 15 years agoHelpfull: Yes(8) No(7)
• total sum of ap=27750
  total sum of ap=n/2[2a+(n-1)d]
  
  =>27750=n/2[2(200)+(n-1)50]
  =>400n+5(n^2)-50n=27750(2)
  =>(n^2)+7n-1110=0
  =>n=30,-37
  so,the number of days cant be -ve,
  ans:30
• 11 years agoHelpfull: Yes(7) No(4)