Q. {(.87)^3+(.21)^3+3*.87*.21}^.5

• ans will be 1.102662233
• 10 years agoHelpfull: Yes(9) No(7)
• Using the formula (a+b)3=a3+b3+3ab(a+b)
  a=0.87
  b=0.21
  
  On simplifying we get the answer 1.08
• 10 years agoHelpfull: Yes(9) No(2)
• answer will be 1.102662233
• 10 years agoHelpfull: Yes(1) No(5)
• how u are applying logic to take power of .5 decimal value
  
• 10 years agoHelpfull: Yes(1) No(0)
• {(.87)^3+(.21)^3+3*.87*.21}^.5
  just add 3*.87^2*.21+3*.87*.21^2-3*.87^2*.21-3*.87*.21^2
  then it can be written as
  {(.87+.21)^3+3*.87*.21(1-.87-.21)}^.5
  {(1.08)^3+3*.87*.21(.08)}^.5
  {1.26-.05}^.5
  1.21^(1/2)=1.1
• 10 years agoHelpfull: Yes(1) No(1)
• can anyone explain plzz @akanksha ,sheetal
• 10 years agoHelpfull: Yes(0) No(1)
• can explain this logic @ bblokesh93@gmail.com
• 10 years agoHelpfull: Yes(0) No(0)
• ans :1.1715
• 9 years agoHelpfull: Yes(0) No(0)
• 1.08
  (add 0.87+0.21)
  
• 8 years agoHelpfull: Yes(0) No(0)