Q. How many values of c in equation x^2-5x+c result in rational roots which are integers ?
Option
(a)1
(b)3
(c)6
(d)infinite

• Given x^2-5x+c=0 to get real roots which are integers discriminant(d)=b^2-4*a*c>0
  =)25-4c>0
  25>4c
  4c
• 11 years agoHelpfull: Yes(0) No(0)
• TE AGO)
  Krishna ChaitanyaGiven x^2-5x+c=0 to get real roots which are integers discriminant(d)=b^2-4*a*c>0
  =)25-4c>0
  25>4c
  4c
• 11 years agoHelpfull: Yes(0) No(0)
• d is right ans, for varying values like 4,6,-50....we can get infite solutions
• 11 years agoHelpfull: Yes(0) No(0)
• x^2-5x+c=0
  To get real roots , discriminant(d)=b^2-4*a*c>0
  25 - 4c > 0
  
  The roots should also be integers
  ===> (25-4c) is a perfect square
  
  c has infinite values (4,0,-6,-50,-150,-300,-500....)
• 10 years agoHelpfull: Yes(0) No(0)