Elitmus
Exam
Numerical Ability
Age Problem
Q. The product of two nonzero numbers is 1,000,000,000. What are the numbers ?
Read Solution (Total 13)
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- 1,000,000,000 =(1000)^3=(125*8)^3=(125^3)*(8^3)=1953125*512
so two nonzero numbers are 1953125 & 512 - 11 years agoHelpfull: Yes(142) No(1)
- we have to find the two non zero numbers having product 10^9.
as 2^1*5^1=10^1
2^2*5^2=10^2
2^3*5^3=10^3
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2^n*5^n=10^n
therefore ans : 2^9*5^9 - 10 years agoHelpfull: Yes(19) No(0)
- 500000000*2
- 11 years agoHelpfull: Yes(5) No(43)
- 1,000,000,000= (10)^9= (2*5)^9= (2)^9*(5)^9=512*1953125
so will be the two non zero no.s is 512 and 1953125 - 10 years agoHelpfull: Yes(5) No(0)
- if you don't have any option then there are multiple answers like , 10000*100000, 1000*1000000....
- 10 years agoHelpfull: Yes(3) No(2)
- @ Rakesh SALUTE man...... Thanks...... Thank u for helping.... #respect..
- 10 years agoHelpfull: Yes(1) No(2)
- They asked just 2 non zero numbers,then y they won't be 500000000 and 2,as mahima told???????
- 10 years agoHelpfull: Yes(1) No(0)
- 5^9*2^9
as 5^2*2^2 results 2 zeros same for 3 zeros and finally for 9 zeros - 11 years agoHelpfull: Yes(0) No(0)
- non-zero means the number should not be 0, as i always understand from this statement.
- 11 years agoHelpfull: Yes(0) No(0)
- 1,000,000,000=(1000)^3=(5*200)^3=(5*5*40)^3=(5*5*5*8)^3=(125*8)^3=125^3 * 8^3=1953125*512
- 10 years agoHelpfull: Yes(0) No(0)
- just take factors of 1,000,000,000. it provides 2^9*1953125 or 512*1953125
- 10 years agoHelpfull: Yes(0) No(0)
- We have find two non zero number :
if i have 10 = 2*5
if i have 100 = 10 * 10 = 2*5*2*5 ( we can write 10*10) = 2^2*5^2
if i have 1000 = 10*10*10 = 2*5* 2*5*2*5 ( we can write 10*10 * 10)= 2^3 *5^3
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so i have 1,000,000,000. = 10 * 10* 10*10*10*10*10*10*10 = 2^9 * 5^9
2^9 = 512 and 5^9 = 1953125 ,both are non zero
1953125 *512 = 1,000,000,000.
- 9 years agoHelpfull: Yes(0) No(0)
- (2*5)^9=10^9 i.e. 1000000000
thus ans 2^9 n 5^9 - 9 years agoHelpfull: Yes(0) No(0)
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