Q. In a certain office, 1/3 of the workers are women, ½ of the women are married and 1/3 of the married women have children. If 3/4 th of the men are married and2/3 rd of the married men have children, what part of workers are without children?
Option
A. 5/18
B. 4/9
C. 11/18
D. 17/18
E. 17/36

• given, 1/3 = women, (1- 1/3=2/3)= men
  
  1/3 = women
  1/2 of women = married
  so 1/3 *1/2 = 1/6 of whole office is married women
  1/3 of married women have children
  so 1/6 *1/3=1/18 of whole office is married women with children
  
  2/3 = men
  3/4 of men = married
  so 2/3 *3/4=1/2 people in office are married men
  2/3 of married men have children
  so 1/2*2/3=2/6 = 1/3 of whole office is married men with children
  
  1/18 + 1/3 = married with children in office = 7/18 of office
  so (1- 7/18=11/18) of office doesn't have children.
  option(c)
• 10 years agoHelpfull: Yes(38) No(1)
• suppose there are total 36 workers.
  12 women.. 6 women married.... 2 women have children.
  24 men .... 18 men married.... 12 men have children
  total 14 workers have children.
  so 22/36=11/18 part of workers don't have children.
• 10 years agoHelpfull: Yes(8) No(0)
• Let total no. of workers be x
  Number of women = x/3 and number of men = 2x/3Women married=1/2 * x/3 = x/6
  Women having children = 1/3 *x/6 =x/18
  Married Men =3/4 *2x/3 = x/2
  Men having Children =2/3 * x/2 = x/3
  Workers with children = x/3 + x/18 = 7x/18
  Hence, workers without children = x- 7x/18 = 11x/18
• 10 years agoHelpfull: Yes(0) No(2)
• 4
  solve it
• 10 years agoHelpfull: Yes(0) No(3)