Accenture
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Numerical Ability
Algebra
Q. Every pupil in a school was given one ticket for a concert. The school was charged a total of $6000 for these tickets, all of which were of equal value. What was the price of one ticket? If the price of each ticket had been one dollar less, the total cost would have been 1,200 less. If the price of each ticket had been $2 more, the total bill would have increased by 40%.
Read Solution (Total 5)
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- $5 each ticket
sol: let no. of people = X
price of one ticket = Y
a/c question,
X*Y=6000
X*(y-1)=4800
X*(Y+2)=6000+6000*40/100
=8400
after solving
y=5 ans. - 10 years agoHelpfull: Yes(6) No(0)
- let no: of tickets = x; and total no: of pupil = y;
then => xy-y(x-1) = 1200;
then no: of pupil = 1200;
then we get the price of each ticket as $5; - 10 years agoHelpfull: Yes(5) No(0)
- when the price of each ticket is reduced by 1,then the saving is $1200 means $1 each student, so total student = 1200;
=>price of each ticket = 6000/1200=$5 - 10 years agoHelpfull: Yes(1) No(0)
- 5...6000-4800=1200,and 6000/1200=5
- 10 years agoHelpfull: Yes(0) No(0)
- let no. of student=n
price of one tkt,x=6000/n
((6000/n)-1)*n=6000-1200
n=1200
x=5 - 10 years agoHelpfull: Yes(0) No(0)
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