if 3rd ter, and 9th term is 8 in a.p,then find the 11th term

• a+2d=8 and 1+8d=8 by calculating these two eqn we get,a=8 and d=0
  so a+10*d=8+0=8
  
• 10 years agoHelpfull: Yes(20) No(2)
• a3=a1+(3-1)d
  8=a1+2d.....(1)equ.
  a9=a1+(9-1)d
  8=a1+8d....(2)equ.
  solve (1) and (2) then a1=4 and d=6.
  a11=a1+(11-1)d
  a11=4+10*6
  a11=64.
• 10 years agoHelpfull: Yes(2) No(18)
• a+(n-1)d---->formulla
  a+(3-1)d=8 => a+2d=8
  a+(9-1)d=8 => a+8d=8 => a=8-8d(substituting in a+2d=8)
  8-8d+2d=8
  d=0
  since d=0 all elements in series is 8,8,8,8,8,------
  hence the 11th term is 8
• 7 years agoHelpfull: Yes(0) No(0)