Q. Six persons A,B,C,D,E & F went to solider cinima. There are six conseutive seats. A sits in one of the seats followed by B, followed by C and soon. If a taken one of the six seats , then B should sit adjacent to A. C should sit adjacent A or B. D should sit adjacent to A, B,or C and soon. How many possibilities are there?

• 32 ways
  is the answer
• 10 years agoHelpfull: Yes(8) No(3)
• ans=2^(6-1)=32
  
  if A is in extreme left only 1 possible arrangements
  ABCDEF
  if A is 2nd from left 5 possible arrangements
  BACDEF (B is in left of A)
  CABDEF (B in right, C in left)
  DABCEF (B,C in right, D in left)
  EABCDF (B,C,D in right, E in left)
  FABCDE (B,C,D,E in right, F in left)
  similarly if A is 3rd from left 10 such possibilities
  other positions of A will repeat those values
  So ans=2*(1+5+10)=32
• 10 years agoHelpfull: Yes(7) No(3)
• it should be 240 ways as given A should be against B. then there will be 5 seats on one side and one seat on the other side there for number of combinations on 5 seats and 5 members is 120 and on the other side there is possibility of 2 members so total number of ways is 240
• 10 years agoHelpfull: Yes(1) No(6)
• First we have to arrange A, there is 1 method for it, for second person B, there are 2 methods one left and one right, for third 2 methods are there same as for B similarly for others, so total number of methods = 1*2*2*2*2*2 = 32
• 6 years agoHelpfull: Yes(1) No(0)
• i think its answer should be 144
  as the places of D,B,A,C are adjacent so total combinations taking them as a single unit are 3!
  and their permutations are 4!
  so 3!*4*=144
• 10 years agoHelpfull: Yes(0) No(5)
• it might be : 2
  
• 9 years agoHelpfull: Yes(0) No(2)
• To understand the solution please watch video(https://www.youtube.com/watch?v=pa44HDixnyo)
• 6 years agoHelpfull: Yes(0) No(0)