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Q. There are different numbers related with A,B,C,D,E.such that, AB*CD=EEE. E*CD-AB=CC.
Find AB*D.
Read Solution (Total 5)
-
- AB*D= BE.
->EEE can be 111, 222, 333, … , 999 or we can say that… 111= 37*03, 222= 37*06 , … & so on.
So, AB=37. To get CD exactly…apply given equation to judge all possible cases. finally u will get CD=12 & AB*D=37*2 = 74 = BE.ANS IS BE. - 11 years agoHelpfull: Yes(20) No(1)
- A=3 B=7 C=1 D=2 E=4
AB*CD=EEE
37*12=444
E*CD-AB=CC
4*12-37=11
Final solution
AB*D
37*2=74 - 11 years agoHelpfull: Yes(13) No(1)
- sangram can u explain ur ans in detail...how u aasigned a=3 b=7 etc
- 11 years agoHelpfull: Yes(8) No(0)
- @ LEEPIKA BISWAL : i just tried to find out 4 different nos whose multiplication will contain only 1 digit like 111,222,333,444,555,666,777,888,999
i found those nos in multiplication table of 37 . then i substitute alphabet with digit and found solution as
A=3 B=7 C=1 D=2 E=4
AB*CD=EEE
37*12=444
E*CD-AB=CC
4*12-37=11
Final solution
AB*D=BE
37*2=74 - 11 years agoHelpfull: Yes(7) No(3)
- given AB*CD=CC
so AB*D=C - 11 years agoHelpfull: Yes(0) No(7)
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