A multiple choice question has 5 options. Choosing the correct option earns the student 1
marks. However choosing the wrong option incurs negative marks so that if a student
chooses an option randomly, his expected score is 0. Suppose a student has successfully
eliminated 2 incorrect options. His expected score if he chooses randomly among the
remaining options is.
1
.33
0
.17

• 0.17 is answer....
  bcz 1/3(1)+2/3(-1/4)=1/6
• 12 years agoHelpfull: Yes(6) No(3)
• answer should be zero..he is choosing randomly dat doesnt matter frm how many
• 13 years agoHelpfull: Yes(5) No(12)
• choosing correct one is 1/5 and wrong one is 4/5.
  by the given question, 1/5(1)+4/5(x)=0
  x=-1/4
  if they eliminate 2 options. then,
  1/3(1)+2/3(-1/4) = (1/3)-(1/6) = 1/6 = 0.1666667 -~ 0.17
• 9 years agoHelpfull: Yes(4) No(1)
• required data is 5 options..
  
  in which 2 incorrect options r identified and elimanated so the options are 3
  
  
  the probabilty of answering is 1/3 is .33
• 12 years agoHelpfull: Yes(3) No(5)
• here according to the question
  1/5(1) + 4/5(-1/4) = 0 ------------------------ among five questions
  if they eliminate two option then option is 3(remaining)
  so it should be
  1/3+(2/3)*(-1/4) = 0.17
  so 0.17 is the answer.
• 9 years agoHelpfull: Yes(1) No(0)
• why -1/4 is multilied with 4/5 @ surit
• 9 years agoHelpfull: Yes(1) No(1)
• answer is zero ...as he is choosing randomly.
• 9 years agoHelpfull: Yes(0) No(1)
• choosing correct one is 1/5 and wrong one is 4/5.
  by the given question, 1/5(1)+4/5(x)=0
  x=-1/4
  if they eliminate 2 options. then,
  1/3(1)+2/3(-1/4) = (1/3)-(1/6) = 1/6.
• 8 years agoHelpfull: Yes(0) No(0)