IBM
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Numerical Ability
Sequence and Series
Q. What is the next number of the following sequence
3,11,31,69...
Read Solution (Total 3)
-
- 3=1^3+2
11=2^3+3
31=3^3+4
69=4^3+5
similarly, next no. is
5^3+6=125+6=131 - 11 years agoHelpfull: Yes(84) No(0)
- 11-3=8 , 31-11=20 , 69-31=38, so
8,20,38 is the diference between the consecutive numbers therefore next diffrence is 8+12=20 , 20+18 = 38 , 38+24 = 62 so answer is 69 + 62 = 131 answer - 11 years agoHelpfull: Yes(10) No(3)
- formate:- (n+1)*n^3
3= 2*1^3
11=3*2^3
31=4*3^3
69=5*4^3
so, 6*5^3=6*125=131 - 11 years agoHelpfull: Yes(5) No(6)
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