Find the missing term denoted by ?

2,11,31,73,?

• 2=1^3+1=1^3+1!
  11=3^2+2=3^2+2!
  31=5^2+6=5^2+3!
  73=7^2+24=7^2+4!
  series is of form (n^2+m!) where n=1,3,5,7,9(series of odd no.)
  & m=1,2,3,4,5 (series of natural no.)
  so next no. is
  9^2+5!=81+120=201
  ans 201
• 11 years agoHelpfull: Yes(2) No(0)
• 2=1^2+1=1^2+1!
  11=3^2+2=3^2+2!
  31=5^2+6=5^2+3!
  73=7^2+24=7^2+4!
  series is of form (n^2+m!) where n=1,3,5,7,9(series of odd no.)
  & m=1,2,3,4,5 (series of natural no.)
  so next no. is
  9^2+5!=81+120=201
  ans 201
• 11 years agoHelpfull: Yes(2) No(0)
• 2*2+7=11
  11*2+9=31
  31*2+11=73
  73*2+13=159
• 11 years agoHelpfull: Yes(1) No(0)
• difference of consecutive numbers
  11-2=9
  31-11=20
  73-31=42
  now calculate difference of differences
  20-9=11
  42-20=12
  so, 42+13=55
  now 55+73=128
  so ans is 128
  orignal series:- 2 .... 11... 31... 73..... 128
  difference series:- 9.....20....42....55
  difference series2:- 11....12...13
  
• 11 years agoHelpfull: Yes(0) No(0)