Three fair dice are thrown simultaneously. What is the probability of getting three numbers whose product is even?

• total occurence=216;
  favourable occurence=3*6*6=108;for even product at least ther should be one even
  now probability=108/216=.5;
• 13 years agoHelpfull: Yes(6) No(1)
• odd*0dd=odd
  odd*even=even
  for product to be even atleast one num shud be even
  chance of even=3
  in remaining two dice any num can occur it wont effect the ans
  so ans is 3*6*6=108
• 13 years agoHelpfull: Yes(4) No(0)
• as explaind above occurance of given cases is 108
  total cases are 6*6*6=216
  probablity =108/216=1/2
• 13 years agoHelpfull: Yes(3) No(0)
• i think manish sir solution is wrong here....
• 12 years agoHelpfull: Yes(0) No(0)
• manish sir solution is rite...answer is 7/8
• 11 years agoHelpfull: Yes(0) No(0)