9 years ago I was five times as old as my eldest son. Today I am 3 times his age. How old am I now?
18.00
20.00
55.00
54.00

• let present age of person is x and his son is y
  given 9 yeaars ago implies x-9=3(y-9)
  now,,x=3y
  solving we get x=54 years
• 12 years agoHelpfull: Yes(9) No(2)
• 54 is d ans
  
• 12 years agoHelpfull: Yes(5) No(1)
• 54 is the ans
  let present age of person is x and his son is y
  given 9 yeaars ago implies x-9=5(y-9)
  now,,x=3y
  solving we get x=54 years
• 12 years agoHelpfull: Yes(4) No(0)
• Father's age is x years
  eldest son age is y years
  nine years ago--->x-9 = 5(y-9)
  x-9 = 5y-45
  now-->x=3y
  substitute this in above
  3y-9=5y-45
  45-9=2y
  y=18
  x=54(father's age)
• 12 years agoHelpfull: Yes(3) No(0)
• #vinay kumar. it is said that 9 years ago "my age was 5 times as my eldest son." not 3 times.
  the actual solution is -
  son-y;
  my-x;
  i) x-9=5(y-9);
  ii) x=3y;
  
  after solution x= 18
• 9 years agoHelpfull: Yes(1) No(0)
• let present age of son = x
  my present age = 3x
  my age 9 years ago = 3x-9 ----------------------------------- a
  
  9 years ago age of son = x-9
  9 years ago my age = 5 (x-9) -------------------------------- b
  
  equate a and b
  
  3x - 9 = 5 (x-9)
  3x - 9 = 5x - 45
  36 = 2x
  x=18
  
  so my present age = 3x = 18*3 = 54
  
  ans. 54
• 4 years agoHelpfull: Yes(1) No(0)
• ans:54
  given that 5(x-9)=x-9
  4x=36
  x=9
  now again saying that 3(x+9)=3(9+9)=54
• 8 years agoHelpfull: Yes(0) No(1)
• assume I means x
  eldest son means y
  9 years ago five times as old as my eldest son means
  x-9=5(y-9)->eq1
  at present i am 3 times his age means
  x=3y->eq2
  substitute eq2 in eq1
  hence 3y-9=5y-45
  45-9=5y-3y
  2y=36
  y=18
  i.e. x=3y means x=3*18=54years
• 7 years agoHelpfull: Yes(0) No(0)
• let the son's age 9 year's ago be 'x'
  then father's age 9 year's ago was '5x'
  son's age after 9 years is=x+9
  father's age after 9 years is =5x+9
  at present the father's age is thrice of his son so
  5x+9=3(x+9)
  on solving we get x=9
  so father's age is=3(x+9)=54
  
  
• 7 years agoHelpfull: Yes(0) No(0)
• Let the present age of father be F and son is S .= his eldest son.... So
  =>F-9=5(S-9) .......... (1)
  also given that at present fathers age is 3 times the sons age ...so
  => F=3(S)......... (2)
  Substitute equation (2) in equation (1) we get...
  => (3S-9)=(5S-45) .... (3)
  => S=18 ( by solving equation (3) )
  Since according to problem the answer is
  => F= 3(S) ....... (from equation (1) )
  => F=3(18) = 54 (Option C)
• 7 years agoHelpfull: Yes(0) No(0)
• According to me if u follow Fast ---->Present----->Future u can solve any problem from ages.
  9 years ago:
  Let Eldest son = x years
  I = 5x
  Present:
  Eldest son = x+9
  I = 5x+9
  According to question
  5x+9 = 3(x+9)
  2x =27-9 => x = 9
  present age of I =9*5+9 = 54 years
• 6 years agoHelpfull: Yes(0) No(0)
• Father's age is x years
  eldest son age is y years
  nine years ago--->x-9 = 5(y-9)
  x-9 = 5y-45
  now-->x=3y
  substitute this in above
  3y-9=5y-45
  45-9=2y
  y=18
  x=54(father's age)
• 2 years agoHelpfull: Yes(0) No(0)