Q. A PERSON WENT TO A SHOP AND ASKED FOR CHANGE FOR 1.15 PAISE. BUT HE SAID THAT HE COULD NOT ONLY GIVE CHANGE FOR ONE RUPEE. BUT ALSO FOR 50P, 25P, 10P AND 5P. WHAT WERE THE COINS HE HAD

• 50p-1, 25p-2, 10p-1, 5p-1
  thus total= 1.15
  
• 10 years agoHelpfull: Yes(25) No(3)
• one 50p coin, four 10p coins, one 25p coin.
• 10 years agoHelpfull: Yes(3) No(8)
• 50p-1
  25p-2
  10p-1
  5p-1
• 10 years agoHelpfull: Yes(3) No(0)
• 5ps -1
  10ps -1
  25ps -4 (or)50ps -2
  ________________________
  1.15ps
• 10 years agoHelpfull: Yes(2) No(1)
• The shopkeeper does not have more than 1 coin of-50p,25p,5p and not more than 4 coins of 10p.
  If he have more than 1 of these coins,he can easily can give change of
  1r=(2x50p),50p=(2x25p),10p=(2x5p)and 50p=(5X10p)
  
  So the only solution-(1X50p)=50
  (4x10p)=40
  (1x25p)=25
• 10 years agoHelpfull: Yes(2) No(0)
• 50p----1
  10p---5
  5p---1
  so that he can give change for 25 i.e
  
  2x10p + 1x5p = 25;
  
  1x10p + 1x5p = 15;
  
  5x10p=50 p ;
  
  1x 50 p +5x1op + 1x5p = 1.15
• 10 years agoHelpfull: Yes(1) No(0)
• 50p-1, 25p-1,10p-2,5p-4
• 10 years agoHelpfull: Yes(1) No(0)
• the coins are 1 50ps coin ,2 25 paisa coin , 1 ten paisa and 1 5 paisa :)
• 8 years agoHelpfull: Yes(1) No(0)
• 1-50p, 1-25p, 3-10p, 2-5p
• 4 years agoHelpfull: Yes(1) No(0)
• 2 X 50 -> 1 Rupee
  1 X 10 -> 10 paisa
  1 x 5 -> 5 paise
  
  total 1.15 Rupee
• 10 years agoHelpfull: Yes(0) No(1)
• 50p - 2, 10p - 1, 5p - 1
• 4 years agoHelpfull: Yes(0) No(0)