Q. In a party attended by 11 persons, each clinch their glass with every other. How many glass clinches?

• Total no. of person = 11
  Total no. of glass clinches = n(n-1)/2
  =11*10/2
  = 55
  so ans will 55
• 10 years agoHelpfull: Yes(15) No(1)
• 1 persons clinch his glass with 10 person
  1 persons clinch his glass with 9 person
  and so on
  now
  10(10+1)/2
  =55
• 9 years agoHelpfull: Yes(4) No(0)
• First person clinches with 10 others
  Then, second will clinch with 9 because he has already clinched with first one.
  then, in this manner 3rd one will clinch with 8 persons
  In this way
  total clinches are 10+9+8+...+1
  So it makes a arithmetic progression and some of total clinches are given by the formula n(n-1)/2
  So its
  11(11-1)/2=11*10/2
  =110/2
  =55 clinches
• 9 years agoHelpfull: Yes(3) No(0)
• 11 persons are there. 2 glasses will get clinched.
  This can be represented in the form of 11C2
  
  11C2 = 11!/(2! * (11-2)!)
  = 11!/(2! * 9!)
  = 55.... Answer.
• 9 years agoHelpfull: Yes(2) No(0)
• n(n-1)/2
  11*10/2=55
  ans is 55
• 10 years agoHelpfull: Yes(1) No(3)
• How is Total no. of glass clinches = n(n-1)/2
  
• 10 years agoHelpfull: Yes(1) No(1)
• why is n(n-1)/2 is used ... can someone explain pls
• 9 years agoHelpfull: Yes(1) No(5)
• 11
  C =(11*10)/2->55
  2
• 10 years agoHelpfull: Yes(0) No(1)
• 11c2=55
  11!/9!*2!=55
• 9 years agoHelpfull: Yes(0) No(1)
• total no of persons = 11
  total no of clinches= [n(n-1)]/2
  =[11(11-1)]/2
  =110/2
  = 55
  so no of total clinches =55
• 9 years agoHelpfull: Yes(0) No(1)
• 11*10=110 every one clinches glass with other except himself
• 7 years agoHelpfull: Yes(0) No(0)
• n*(n-1)/2
  11*(11-1)/2
  55
• 5 years agoHelpfull: Yes(0) No(0)