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Logical Reasoning
Mathematical Reasoning
Q. In a party attended by 11 persons, each clinch their glass with every other. How many glass clinches?
Read Solution (Total 12)
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- Total no. of person = 11
Total no. of glass clinches = n(n-1)/2
=11*10/2
= 55
so ans will 55 - 10 years agoHelpfull: Yes(15) No(1)
- 1 persons clinch his glass with 10 person
1 persons clinch his glass with 9 person
and so on
now
10(10+1)/2
=55 - 10 years agoHelpfull: Yes(4) No(0)
- First person clinches with 10 others
Then, second will clinch with 9 because he has already clinched with first one.
then, in this manner 3rd one will clinch with 8 persons
In this way
total clinches are 10+9+8+...+1
So it makes a arithmetic progression and some of total clinches are given by the formula n(n-1)/2
So its
11(11-1)/2=11*10/2
=110/2
=55 clinches - 10 years agoHelpfull: Yes(3) No(0)
- 11 persons are there. 2 glasses will get clinched.
This can be represented in the form of 11C2
11C2 = 11!/(2! * (11-2)!)
= 11!/(2! * 9!)
= 55.... Answer. - 10 years agoHelpfull: Yes(2) No(0)
- n(n-1)/2
11*10/2=55
ans is 55 - 10 years agoHelpfull: Yes(1) No(3)
- How is Total no. of glass clinches = n(n-1)/2
- 10 years agoHelpfull: Yes(1) No(1)
- why is n(n-1)/2 is used ... can someone explain pls
- 10 years agoHelpfull: Yes(1) No(5)
- 11
C =(11*10)/2->55
2 - 10 years agoHelpfull: Yes(0) No(1)
- 11c2=55
11!/9!*2!=55 - 10 years agoHelpfull: Yes(0) No(1)
- total no of persons = 11
total no of clinches= [n(n-1)]/2
=[11(11-1)]/2
=110/2
= 55
so no of total clinches =55 - 9 years agoHelpfull: Yes(0) No(1)
- 11*10=110 every one clinches glass with other except himself
- 7 years agoHelpfull: Yes(0) No(0)
- n*(n-1)/2
11*(11-1)/2
55 - 6 years agoHelpfull: Yes(0) No(0)
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