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Q. If a cyclist takes 3 mins in the direction of wind for a distance of 6 m and 4 minutes againstthe direction of the wind. Assuming the cyclist applies same force on the pedals at all times,find the time taken by the cyclist in No wind?
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- 3 3/7 minutes
If Speed of cyclist in no wind=x m/min.& Speed of the wind=y m/min.
Time taken in the direction of wind=6/(x+y)=3 or x+y=2 ---(i) &
Time taken against the direction of wind=6/(x-y)=4 or 2x-2y=3 ---(ii)
Solving (i) & (ii),x=7/4, y=1/4
Time taken by cyclist in no wind=6/x=6/(7/4)=24/7= 3 3/7 minutes
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