Accenture
Company
Logical Reasoning
General Mental Ability
Q. We are given 100 pieces of a puzzle. If fixing two components together is counted as 1 move ( a component can be one piece or an already fixed set of pieces), how many moves do we need to fix the entire puzzle.
Read Solution (Total 8)
-
- 99 moves
fixing each 10 components requires 9 moves,so it is 90 for 10 such components.
fixing those 10 bigger components requires 9 more moves.so totally 99 moves. - 10 years agoHelpfull: Yes(12) No(1)
- n-1 Moves required.
As... if 2 pieces then 1 move required,
if 5 pieces then 4 moves required,
if 10 pieces then 9 moves required,
so if 100 pieces then required moves are... - 10 years agoHelpfull: Yes(6) No(1)
- 50...
the exact answer is 18... but i dono..how - 10 years agoHelpfull: Yes(5) No(3)
- Ans s 99 moves
consider 10 piece requires 9 moves , there are totally 100 so 90 moves ,
nw all piece r in 10,10,10,10,10,10,10,10,10,10,
v need 9 moves to joint r finish d puzzle so totally 99
- 10 years agoHelpfull: Yes(4) No(1)
- 2 - 1 move
2 - 1 move
total 50 moves
and then
those 50 will be given 25 moves
in 25 components , we have 12 and half move
so total move = 87.5 - 10 years agoHelpfull: Yes(3) No(7)
- fixing 2 components together=1 move
98 components are left ,to again fix one of these to the other two=1move
97 comp left,so 97 more moves
total=1+1+97=99 - 10 years agoHelpfull: Yes(2) No(3)
- Ans should be 99 because first, we combine 50 with other 50 and then divide them into two parts and continue this till we get 1 and add all moves together it will give 97 (97 is the highest power of 2 in range of 0-100) then we should add 2 in our answer because we have skipped some fractional values like 25 and 3.
Thus 97 + 2 = 99 wil be the answer. - 6 years agoHelpfull: Yes(1) No(0)
- Fixing 2 components is called 1 move, now i deduce fixing 3 components in same move does not count as 1 move , so here it is , join 3 single pieces by inducing a piece in between 2 , |[|]| , the one in [] is induced, joining 3 components in 1 move , hence move counted as 0 , we can make 33 components like then , using 0 moves, now in 9 by 9 area , we just same method of inducing , and 81 are connected using 0 moves , the last row and column are joined using same technique , 9*1 and 1*9 , using 0 moves , now the last 100th segment is used to connect this last row and column , using 0 moves , now this last row and column is deviced as a single component and is joined with the 9*9 component we previously made, as this one is joining 2 components in 1 move, technically we only using 1 move to solve it.. ONLY 1
- 8 years agoHelpfull: Yes(0) No(1)
Accenture Other Question