3i-Infotech
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Numerical Ability
Permutation and Combination
1, 2 , 3, 4 digits are available. How many number of 4 digited numbers which are divisible by 4. (There should be no repetition of digits in the numbers) can be formed?
Read Solution (Total 4)
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- number is divisible by 4 if last two digit of no. is divisible by 4
so last two digit should be 12,24,32
last two digit can be filled in 3 ways,so remaining two places can be filled in 2! ways
number of 4 digit numbers which are divisible by 4 = 3*2!=6
- 10 years agoHelpfull: Yes(7) No(0)
- a number is divisible by 4 if last two digit of no. is divisible by 4
so last two digit should be 12,24,32
possible numbers
3412
4312
1324
3124
1432
4132
no. of 4 digit numbers divisible by 4 = 6 - 10 years agoHelpfull: Yes(5) No(0)
- last 2 digit should be divisible by 4 so last 2 digit can be
12,32,24
2!*3=6
so 6 is the correct answer - 10 years agoHelpfull: Yes(0) No(1)
- '6' 4digit numbers are formed.
a number which is divisible by 4 is having the last two digits of number must be divisible by 4.
so 32,12,24 are last two digits of the numbers which are formed by above condition.
so numbers are 1432,4132,4312,3412,1324,3124. - 10 years agoHelpfull: Yes(0) No(0)
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