Excluding stoppages , the speed of the bus is 54 km/hr and including stoppages , it is 45 km/hr . For how many minutes does the bus stop per hour ?

• Due to stoppages, it covers 9 km less.
  
  Time taken to cover 9 km = (9 /54)*60 min = 10 min.
  
• 10 years agoHelpfull: Yes(15) No(0)
• it covers 54 km/hr, so for 1km= 1hr/54= 60mins/54= 10mins/9
  if for 1km,it takes 10/9, then for 9km, its (10/9)*(9) = 10mins
• 10 years agoHelpfull: Yes(5) No(0)
• Let T be time taken to cover a distance D excluding stoppages. Then D/T = 54km/hr.
  Let t be the total time of stoppages. So, time taken to cover the distance D including stoppages will be T+t. In this case, D/(T+t) = 45km/hr.
  Now, evaluating the two equations, 45(t+T)=54T. This gives T=5t. Looking at the problem again, T+t is because of the extra time due to stoppages (t). It means, t hours is wasted in T+t hours. If t hours for T+t=6t hours, how much t for one hour?-> 1/6 hours of t for one hour. Converting t into minutes, we get 10 min of t for one hour. Hence, THE ANSWER IS 10 MINUTES.
• 10 years agoHelpfull: Yes(1) No(0)
• ans)10 minutes.
  in 10 minutes bus cover 9 km. so without stoppage it will cover 54 km. and with stoppage of 10 minutes it will cover only 45 km.
  (x/60)*54 = 45.
  x = 50. means to cover 45 km. bus will take 50 minutes and 10 minutes for rest,
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• 54-45=9
  to cover 9 km=54/9=6 miutes
  
• 9 years agoHelpfull: Yes(0) No(2)
• Stoppage time (T) = (Speed Excluding - Speed Including) / Speed Excluding
  So, T = (54 - 45) / 54 = 9 / 54 hrs
  Converting to minutes (9 / 54) * 60 = 10 min
• 3 years agoHelpfull: Yes(0) No(0)