Boat A leaves shore P and Boat B leaves shore

Q.(P and Q are opposite shores of a river.) A and B travel at constant speed.But the speeds are not same. Both boats meet at 600m from P for the first time. In their return journeys (ie after touching the shores), they meet agian at 200m from
Q. Find distance between P and Q.

• 1600 mtrs
  Their speed ratios are 3:5.
• 10 years agoHelpfull: Yes(2) No(6)
• let a and b be the speed of the boats and x be the distance between P and Q
  600/a = x-600/b ---(1)
  x-600+200/a = x-200+600/b
  ie x-400/a = x+400/b ---(2)
  (2)/(1) gives
  (x-400)/600 = (x+400)/(x-600)
  solving x=1600
  ans 1600m
  
• 10 years agoHelpfull: Yes(1) No(1)