certain number of completes a work in 10 days if 10 men r reduced it takes 10 more days to

number of men =x
then use the formulae = M1*D1*H/W1 = M2*D2*H2/W2
here M1 = 'x'
D1 = '10'
M2= 'x-10'
D2 = '10+10=20'
SUBSTITUTE THE VALUES IN FORMULAE WE GET 10x = (x-10)*20
x = '20'
10 years agoHelpfull: Yes(8) No(1)
X men-10days
10*X men can complete the same work in 1 day
1 man's 1 days work is =1/10X------eqa 1
(X-10)men-20days
(X-10)*20 can complete the work in 1 day
1 men 1 days work=1/(X-10)*20------eqa2
on equating both equations we get the value of X as 20
10 years agoHelpfull: Yes(3) No(1)
no.of men are inversely proportional to work.x/x-10=2,then x=2o
10 years agoHelpfull: Yes(3) No(0)
20 men complete work in 10 days.
10 men will complete work in 20 days.

so originally 20 men are there.
10 years agoHelpfull: Yes(2) No(2)
20 (x-10)20=10x
10 years agoHelpfull: Yes(2) No(0)
answer is 110
10 years agoHelpfull: Yes(2) No(12)
work= no.of men*days
so, take no.of men=X
work=X*10 days............(1)
in both cases work is same so,
10 men reduced=(X-10)
it takes more 10 days=> 10+10=20 days
work=(X-10)*20
=20X-200.....(2)
work is always same
so 1st equation =2nd equation
10X=20X-200
10X=200
X=20
so answer is 20 men
10 years agoHelpfull: Yes(2) No(0)
let original no. of men=x;
(1/(10*x))*(x-10)*20=1
=>x=20
10 years agoHelpfull: Yes(1) No(0)

certain number of completes a work in 10 days .if 10 men r reduced it takes 10 more days to complete the work. what is the original number of men