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Q. 5 cats can catch 5 mice in 5 minutes. How many cats does it take to catch 100 mice in 100 minutes?
Read Solution (Total 9)
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- let x be no. of cat
5 cat catch 5 mice in 5 min
5 cat catch 1 mice in (5/5=1 min)
1 cat catch 1 mice in 1*5=5 min
1 cat catch 100 mice in 5*100 min
x cat catch 100 mice in (5*100)/x min
A/Q (5*100)/x = 100
=> 5*100=x*100
=> x=5 - 11 years agoHelpfull: Yes(50) No(0)
- 5 cat can catch 5 mice in 5 min, then it can catch 10 mice in 10 min...
likewise 10*10= 100 mice in 10*10 min .
time and mice count only increase, not cat count, so 5 cat is the answer.
simple logic - 11 years agoHelpfull: Yes(9) No(1)
- 5 cat catch 5 mice in 5 min
5 cat catch 1 mice in (5/5=1 min)
1 cat catch 1 mice in 1*5=5 min
1 cat catch 100 mice in 5*100 min
100 cat catch 100 mice in (5*100)/100=5 min
ans 5 minutes
- 11 years agoHelpfull: Yes(6) No(1)
- from the time and work formula- (M1*H1)/W1=(M2*H2)/W2
=>(5*5)/5=(X*100)/100
=> X=5 - 10 years agoHelpfull: Yes(5) No(0)
- 5 cat catch 5 mice in 5 mins
1 cat catch 1 mice in (5*5)/5mins
100cats catch 100 mice in (5*5*100)/(5*100)mins
ans.= 5minutes - 11 years agoHelpfull: Yes(4) No(1)
- L1*M1*D2=L2*M2*D1
5*5*100=5*100*X
ON SOLVING
X=5ans.......... - 11 years agoHelpfull: Yes(2) No(1)
- 5 cat catch 5 mice in 5 min
5 cat will catch 10 mice in 10 min
5 cat will catch 15 mice in 15 min
5 cat will catch 20 mice in 20min
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5 cat will catch 100 mice in 100 min.
i.e 100/5 =20 times 5 cats will go to catch 1 mice each i.e 5 mice - 10 years agoHelpfull: Yes(2) No(0)
- the ratio is same as the time limit extends so 5 cats are required
- 11 years agoHelpfull: Yes(1) No(0)
- from the law of proportinality
cat mice time(min)
5 5 5
x(let) 100 100
x=5(100/5)(5/100)
x=5 anssss - 11 years agoHelpfull: Yes(0) No(0)
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