Q. 5 cats can catch 5 mice in 5 minutes. How many cats does it take to catch 100 mice in 100 minutes?

• let x be no. of cat
  5 cat catch 5 mice in 5 min
  5 cat catch 1 mice in (5/5=1 min)
  1 cat catch 1 mice in 1*5=5 min
  1 cat catch 100 mice in 5*100 min
  x cat catch 100 mice in (5*100)/x min
  A/Q (5*100)/x = 100
  => 5*100=x*100
  => x=5
• 10 years agoHelpfull: Yes(50) No(0)
• 5 cat can catch 5 mice in 5 min, then it can catch 10 mice in 10 min...
  likewise 10*10= 100 mice in 10*10 min .
  time and mice count only increase, not cat count, so 5 cat is the answer.
  simple logic
• 10 years agoHelpfull: Yes(9) No(1)
• 5 cat catch 5 mice in 5 min
  5 cat catch 1 mice in (5/5=1 min)
  1 cat catch 1 mice in 1*5=5 min
  1 cat catch 100 mice in 5*100 min
  100 cat catch 100 mice in (5*100)/100=5 min
  ans 5 minutes
  
• 10 years agoHelpfull: Yes(6) No(1)
• from the time and work formula- (M1*H1)/W1=(M2*H2)/W2
  =>(5*5)/5=(X*100)/100
  => X=5
• 10 years agoHelpfull: Yes(5) No(0)
• 5 cat catch 5 mice in 5 mins
  1 cat catch 1 mice in (5*5)/5mins
  100cats catch 100 mice in (5*5*100)/(5*100)mins
  ans.= 5minutes
• 10 years agoHelpfull: Yes(4) No(1)
• L1*M1*D2=L2*M2*D1
  5*5*100=5*100*X
  ON SOLVING
  X=5ans..........
• 10 years agoHelpfull: Yes(2) No(1)
• 5 cat catch 5 mice in 5 min
  5 cat will catch 10 mice in 10 min
  5 cat will catch 15 mice in 15 min
  5 cat will catch 20 mice in 20min
  .
  .
  .
  .
  5 cat will catch 100 mice in 100 min.
  i.e 100/5 =20 times 5 cats will go to catch 1 mice each i.e 5 mice
• 10 years agoHelpfull: Yes(2) No(0)
• the ratio is same as the time limit extends so 5 cats are required
• 10 years agoHelpfull: Yes(1) No(0)
• from the law of proportinality
  
  cat mice time(min)
  5 5 5
  x(let) 100 100
  
  x=5(100/5)(5/100)
  x=5 anssss
• 10 years agoHelpfull: Yes(0) No(0)