Q. 6 women can do 75 unit of work in 8 days by working 5hr/day in how many days 4 women do 30 units of work by working 8hr/day

• (6x8x5)/75=(Ax4x8)/30
  A=3
• 10 years agoHelpfull: Yes(47) No(0)
• use (man*days*hours /work).thus m1*d1*hi /w1 = m2*d2*h2 /w2. hence d2 is 3
• 10 years agoHelpfull: Yes(17) No(0)
• 3 days
  6 Women---8*5(=40)DayHour---75 Units
  4 Women---8*5 DayHour---75*2/3(=50)Units
  4 Women---40(3/5)DayHour---30 Units
  4 Women---24 Dayhour---30 Units
  So for 30 Units of work,4 Women working 8 hr/day requires 24/8= 3 days
• 10 years agoHelpfull: Yes(9) No(0)
• Ans will be 3 days..
  Because..
  6 Women can complete in 8 days...So,4 Women will complete in more days..(Indirect prorportin)
  75 units of work done in 8 days..So,30 unit of work will be done in less days.(Direct prorportion)
  Working 5hr/day takes 8 days..So,Working 8hrs/days takes less days(Indirect prorportion )
  So, 4*75*8*x=6*30*5*8
  x=3 days
• 10 years agoHelpfull: Yes(4) No(0)
• 6 womwn---75 unit--- 5hr/day = 8 days
  1 '' 1 '' 1 '' = 8*6*5/75
  4 '' 30 '' 8 '' = (8*6*5*30)/(75*4*8)=3 days
• 10 years agoHelpfull: Yes(3) No(0)
• 6*75*5:4*30*8::8:x
  now solve this
  30*75*x=120*8*8
  7680=2250x
  x=3
• 10 years agoHelpfull: Yes(3) No(0)
• Total woman hrs reqd. for 75 units of work = 6*8*5=240
  woman hrs reqd. for 1 units of work = 240/75
  woman hrs reqd. for 40 units of work = 240*40/75 = 128
  no of days required = 128/(4*8)= 4 days
• 10 years agoHelpfull: Yes(2) No(7)
• (6*8*5)/75=(A*4*8)/30
  A=3
• 10 years agoHelpfull: Yes(2) No(0)
• trick:
  M1D1H1W2=M2D2H2W1
  6*8*5*30=4*D2*8*75
  SOLVE TH EQUATION ANS=3
• 10 years agoHelpfull: Yes(2) No(0)
• 8*6/4*30/75*5/8=3
• 10 years agoHelpfull: Yes(2) No(0)
• m1*d1*h1/w1 = m2*h2*d2/w2 formula substitute get 3
• 5 years agoHelpfull: Yes(0) No(0)